<u>Answer:</u>
When Anne pushes the wheelbarrow 25 meters the work done is 1120 joules
<u>Solution:</u>
We know 
Anne is pushing the wheelbarrow with a force of 70 N at an angle of 
with the horizontal
So the force of Anne will be 
She pushes the wheelbarrow 25 meter, So D = 25 meters
So, the 
Anne has done total 1120 joules work.
Answer:
Step-by-step explanation:
Answer:
i am in 7th grade
Step-by-step explanation:
Question 1)
Given: F(x) = 3x^2 + 1, G(x) = 2x - 3, H(x) = x
F(G(x)) = 3(2x - 3)^2 + 1
F(G(x)) =3(4x^2 - 12x + 9) + 1
F(G(x)) = 12x^2 - 36x + 27 + 1
F(G(x)) =12x^2 - 36x + 28
Question 2)
Given: F(x) = 3x^2 + 1, G(x) = 2x - 3, H(x) = x
H -1 (x) = x (inverse)
> multiply the second equation by 2 and add it to the first equation.
2(-6x - 7y = -10)
-12x -14y = -20
8x + 14y = 4
-12x - 14y = -20
--------------------
- 4x + 0 = - 16
x = -16/-4
x = 4
> use x = 4 in either equation to find y
8(4) + 14y = 4
32 + 14y = 4
14y = 4 - 32
14y = -28
y = -28/14
y = -2
