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3 years ago

How do you graph this? y=−5x

Mathematics

1 answer:

Alexus [3.1K]3 years ago

7 0

Answer:

Step-by-step explanation:

dont need to graph the center dot, its just the origin

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Write an equivalent algebraic equation for the sentence below.

tatuchka [14]

Answer:

x-7=13

Step-by-step explanation:

x-7= 13

hope that helps

5 0

3 years ago

Identify the center and radius of the circle (x+4)^2+(y-2)^2=16

fgiga [73]

Answer: center is (-4,2) radius is 4

Step-by-step explanation:

Equation of circle

is (X-A)^2+(X-B)^2=r^2

The center Of The circle is (A, B)

The radius Of The circle is r

Comparing the given equation and the equation of a circle we get the center Of The circle as (-4,2) and then radius as 4

7 0

3 years ago

In the parallelogram, find y.

harkovskaia [24]

Answer:

y = 9

plz mark my answer as brainlist plzzzz vote me also...

8 0

2 years ago

Read 2 more answers

0.06 0.16 0.6 0.66 least to greastest

Komok [63]

Stack them all up in a row:

0.06
0.16
0.60
0.66

Now order them from least to greatest by each place

0.06, 0.16, 0.60, 0.66

(LOL, you TYPED them least to greatest!)

Hope I helped! (Pick me as brainliest!)

7 0

3 years ago

Calculate the flux of the vector field F⃗ (x,y,z)=(exy+9z+4)i⃗ +(exy+4z+9)j⃗ +(9z+exy)k⃗ through the square of side length 3 wit

ikadub [295]

The square (call it $S$ ) has one vertex at the origin (0, 0, 0) and one edge on the y-axis, which tells us another vertex is (0, 3, 0). The normal vector to the plane is $\vec n=\vec\imath-\vec k$ , which is enough information to figure out the equation of the plane containing $S$ :

$(x\,\vec\imath+y\,\vec\jmath+z\,\vec k)\cdot(\vec\imath-\vec k)=0\implies x-z=0\implies z=x$

We can parameterize this surface by

$\vec s(x,y)=x\,\vec\imath+y\,\vec\jmath+x\,\vec k$

for $0\le x\le\frac3{\sqrt2}$ and $0\le y\le3$ . Then the flux of $\vec F$ , assumed to be

$\vec F(x,y,z)=(e^{xy}+9z+4)\,\vec\imath+(e^{xy}+4z+9)\,\vec\jmath+(9ze^{xy})\,\vec k$ ,

$\displaystyle\iint_S\vec F(x,y,z)\cdot\mathrm d\vec S=\iint_S\vec F(\vec s(x,y))\cdot\vec n\,\mathrm dx\,\mathrm dy$

$=\displaystyle\int_0^3\int_0^{3/\sqrt2}\left((4+e^{xy}+9x)\,\vec\imath+(9+e^{xy}+4x)\,\vec\jmath+(e^{xy}+9x)\,\vec k\right)\cdot(\vec\imath-\vec k)\,\mathrm dx\,\mathrm dy$

$=\displaystyle\int_0^3\int_0^{3/\sqrt2}4\,\mathrm dx\,\mathrm dy=\boxed{18\sqrt2}$

3 0

3 years ago