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Ad libitum [116K]
3 years ago
5

Jim, Dan and David share some sweets in the ratio 3:2:1. Jim gets 27 sweets. How many sweets are there altogether?

Mathematics
1 answer:
Gemiola [76]3 years ago
4 0

Answer:

54 sweets altogether

Step-by-step explanation:

Jim: 27

Dan:

David:

3:2:1

The amount is divided by 6

27/3=9

Dan— 9*2=18

David— 9*1=9

18+9+27=54

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Answer:

P(A \cap B)

And we can use the following formula:

P(A \cap B)= P(A)* P(B)

And replacing the info we got:

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Step-by-step explanation:

We define two events for this case A and B. And we know the probability for each individual event given by the problem:

p(A) = \frac{5}{7}

p(B) = \frac{2}{3}

And we want to find the probability that A and B both occurs if A and B are independent events, who menas the following conditions:

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And we can use the following formula:

P(A \cap B)= P(A)* P(B)

And replacing the info we got:

P(A \cap B) = \frac{5}{7} \frac{2}{3}= \frac{10}{21}=0.476

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3 years ago
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