Put the coordinate and check each
#1
No
#2
Unless you did typing mistake on right hand side it's
#3
Yes
#4
No
#5
Yes
#6
No
I believe it's A. Sometimes you have to take an educated guess.
Answer:
6 ≤ x < ∞
Step-by-step explanation:
The value of x cannot be less than 6 because that would make the term in the square root part negative. There is no real square root of a negative vale.
Answer:
x^2+6x-4=0 x^2+6x=4 x^2+6x+9=13 (x+3)(x+3)=13 x+3=+or-(13^1/2) x=-3+or-13^1/2
Step-by-step explanation:
sry if im wrong :< if im right, can i have brainliest? have a wonderful day/night :D
The diagonal of a rectangle = sqrt(w^2 + l^2)
w = width
l = length
In this problem,
The diagonal = 20 in
w = x
l = 2x + 8
Let's plug our numbers into the formula above.
20in = sqrt((x)^2 + (2x + 8)^2)
Let's simplify the inside of the sqrt
20 in = sqrt(5x^2 + 32x + 64)
Now, let's square both sides.
400 = 5x^2 + 32x + 64
Subtract 400 from both sides.
0 = 5x^2 + 32x - 336
Factor
0 = (5x - 28)(x + 12)
Set both terms equal to zero and solve.
x + 12 = 0
Subtract 12 from both sides.
x = -12
5x - 28 = 0
Add 28 to both sides.
5x = 28
Divide both sides by 5
x = 28/5
The width cant be a negative number so now we know that the only real solution is 28/5
Let's plug 28/5 into our length equation.
Length = 2(28/5) + 8 = 56/5 + 8 = 96/5
In conclusion,
Length = 96/5 inches
Width = 28/5
