To Find :
How many gallons of a 80% antifreeze solution must be mixed with 100 gallons of 20% antifreeze to get a mixture that is 70% antifreeze.
Solution :
Let, x gallons of 80% antifreeze solution is required :
So,
Therefore, 500 gallons of 80% antifreeze solution is required.
Here is the work:
(13x - 5x) + 12 - 2y = 6
(8x) + 12 - 2y = 6
-2y = -8x - 12 + 6
-2y = -8x - 6
y = 4x + 3
Answer:
You have 80 yards left to run.
Step-by-step explanation:
To solve this problem, we first must realize that if you have completed 80% of the run, that you have 20% left (this is because 100%-80% = 20%).
Next, we must find 20% of 400 yards. We must remember that in math, the word "of" represents multiplication. We also know that 20% = 20/100 = 0.2.
To find 20% of 400 yards, we can perform the following operation:
20% * 400
0.2 * 400
80
Therefore, you have 80 yards left.
Hope this helps!
Answer:
should be correct!
Step-by-step explanation:
43000 is your answer I know because I know
