Answer
Step-by-step explanation:
4xc=4c
4x-2= -8
4c-8
Answer:
a) P ( 3 ≤X≤ 5 ) = 0.02619
b) E(X) = 1
Step-by-step explanation:
Given:
- The CDF of a random variable X = { 0 , 1 , 2 , 3 , .... } is given as:
Find:
a.Calculate the probability that 3 ≤X≤ 5
b) Find the expected value of X, E(X), using the fact that. (Hint: You will have to evaluate an infinite sum, but that will be easy to do if you notice that
Solution:
- The CDF gives the probability of (X < x) for any value of x. So to compute the P ( 3 ≤X≤ 5 ) we will set the limits.

- The Expected Value can be determined by sum to infinity of CDF:
E(X) = Σ ( 1 - F(X) )

E(X) = Limit n->∞ [1 - 1 / ( n + 2 ) ]
E(X) = 1
Answer:
t=4
Step-by-step explanation:
5t-3=3t+5 - subtract 3t from both sides
2t-3=5 - add 3 to both sides
2t=8 - divide by 2
t=4
Answer:
Equivalent
Step-by-step explanation:
Look at 6/18. 18 divided by 6 is 3, which is the denominator. 6 divided by 6 is 1, so the numerator. So 1/3.