Answer:
Under the normal sign convention, the distributed load on a beam is equal to the: O The second derivative of the bending moment with respect to the length of the beam O Negative of the rate of change of the shear force with respect to the length of the beam.
Sorry if the answer is wrong
Advantages of liquid electrical tape over conventional electrical tape for covering exposed conductors is given below.
Explanation:
- Electrical tape and "regular" adhesive tape is that electrical tape is stretchy. This allows the tape to wrap around a wire junction and still grab the insulation to either side. This helps keep the tape in place.Where as Regular tape is likely to get stiff, lose adhesion, and slide away from the joint, leaving it exposed.
- The electrical tape is able to withstand much more heat and like the others said the adhesive is better and it can stretch 200 percent.
- Electrical tape is a suitable long-term or permanent solution in various applications.Heat-shrink sleeving, spiral wrap, flexible conduit, self-amalgamating tape, rubber sleeves, junction boxes, table ties/clips, grommets, cable markers, etc. are all better solutions for almost any given use of electrical tape other than to conventional electrical tape which has temporarily hold, bundle, insulate, or mark a cable.
- This kind of type is often used by electricians. It's typically made of slightly stretchy PVC vinyl, and is backed with a pressure sensitive rubber-type adhesive. It has good insulative properties, and is perfect for protecting wire splices and providing extra insulation on electrical cords. it's also available in a variety of other colors (like red, green, yellow, green, and white) that can be used for color-coding.
Answer:
2.35 + j8.34 Ω
Explanation:
Voltage = V = 240 V rms
supplying power = S = 8 kVA
power factor = pf = 0.6
Let P₁ represents one load draws 3kW at unity powder factor
The power angle is:
θ = cos⁻¹ pf = cos⁻¹ 0.6 = 53.13°
Complex power supplied source is:
S = S < θ = 8<53.13° kVA
Complex power for first load:
S₁ = P₁ = 3kVA
Since the power angle of first load is θ₁ = 0°
According to principle of conservation of AC power, the power of second load is:
S₂ = S - S₁
= 8<53.13° - 3
= 6.65<74.29° kVA
Since the second load is a Y connected load the phase voltage:
V = V /
= 240/1.732051
= 138.564
= 138.56 V
Complex power of second load:
S₂ = 3 V² / Z
impedance per phase of the second load:
Z = 3 V² / S₂
= 3 (138.56)² / 6.65<74.29°
= 3(19198.8736) / 6.65<74.29°
= 57596.6208 / 6.65<74.29°
Z = 2.35 + j8.34Ω
Answer:
True
Explanation:
Principles of plasma arc cutting, Uses a constricting nozzle to create, concentrate, and direct the high-velocity plasma. Plasma gas is always used
in plasma arc cutting When shielding gas is also used, the process is called dual flow plasma arc cutting. I hope this helps.
Answer:
The channel distance affected by the weir
Yn ( Normal depth ) = 5.71 ft
Yc ( critical depth ) = 4.11 ft
x = 22794 ft
Explanation:
Attached below is a detailed solution to the problem
The channel distance affected by the weir
Yn ( Normal depth ) = 5.71 ft
Yc ( critical depth ) = 4.11 ft
x = 22794 ft