Under the normal sign convention, the distributed load on a beam is equal to the:_______A. The rate of change of the bending mom
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Answer:
The heat flow in 24 hours through the refrigerator door is approximately 1,608.57 BTU
Explanation:
The given parameters are;
The duration of the heat transfer, t = 24 hours = 86,400 seconds
The area of the refrigerator door, A = 30.0" × 58.0" = 1,740 in.² = 1.122578 m²
The material of the insulator in the door = Cellulose fiber
The thickness of the insulator in the door, d = 2.0" = 0.0508 m
The temperature inside the fridge = 38° F = 276.4833 K
The temperature of the room = 78°F = 298.7056 K
The thermal conductivity of cellulose fiber = 0.040 W/(m·K)
By Fourier's law, the heat flow through a by conduction material is given by the following formula;
Therefore, we have;
The heat flow in 24 hours through the refrigerator door, Q = 1,697,131.73522 J = 1,608.5705140685 BTU
<u>Explanation:</u>
Determine the weight of footing
Where is the weight of footing, γ is the unit weight of concrete, L is the length of footing is the width of footing, and D is the depth of footing
Substitute for γ in the equation
Therefore, the weight of the footing is 35.4 kN
Determine the initial vertical effective stress.
Here, is initial vertical stress at a depth below ground surface γ is the unit weight of soil, D is depth and u is pore water pressure.
Substitute for u in the equation
Therefore, the initial vertical stress is 36 kPa
Determine the vertical effective stress.
Here, is initial vertical stress at a depth below ground surface γ is the unit weight of soil, D is depth and u is pore water pressure.
Substitute in the equation.
Therefore, the vertical stress at a depth below the ground surface is
9 kPa
Determine the influence factor at the midpoint of soil layer,
Here is the influence factor at the midpoint of soil layer
is initial vertical stress,
is vertical effective stress, and
is bearing pressure
Substitute in the equation
Therefore the influence factor at the midpoint of the soil layer is 0.693