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belka [17]
3 years ago
13

Under the normal sign convention, the distributed load on a beam is equal to the:_______A. The rate of change of the bending mom

ent with respect to the shear force. B. The second derivative of the bending moment with respect to the length of the beam. C. The rate of change of the bending moment with respect to the length of the beam. D. Negative of the rate of change of the shear force with respect to the length of the beam.
Engineering
1 answer:
frez [133]3 years ago
6 0

Answer:

Under the normal sign convention, the distributed load on a beam is equal to the: O The second derivative of the bending moment with respect to the length of the beam O Negative of the rate of change of the shear force with respect to the length of the beam.

Sorry if the answer is wrong

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Using the Breguet range and endurance equation, estimate the amount of kerosene
love history [14]

The amount of kerosene fuel needed for an aircraft weighing 10 metric tons to fly from Boston to Los Angeles, assuming a distance of 5,000 [km] is 10000 kg.

<h3>What is Breguet equation?</h3>

Breguet equation is used to determine the range of airplane fly in some specified set of parameters.

R=\dfrac{h_f}{g}\dfrac{L}{D}\times \eta \ln \left(\dfrac{W_{initial}}{W_{final}}\right)

Here, (L/D) is lift to drag ratio,<em> g</em> is gravitation acceleration,<em> h </em>is height and <em>W</em> is weight.

The weight of aircraft is 10 metric tons (this is the dry weight that includes passengers and cargo)  The distance of 5,000 [km], with velocity at 300 [m/s]  from Boston to Los Angeles has to be cover by the airplane.

The initial weight is 10 metric tons or 10000 kg. Thus, the final weight with total fuel burn is,

W_{final}=W_{initial}-W_{fuel}\\W_{final}=1-\dfrac{W_{fule}}{W_{initial}}

The lift-to-drag ratio is 15 and the overall efficiency is 0.3,  The standard air density at an altitude of approximately 6,000 [m] is half.

Thus, put the values, in above formula,

5000=\dfrac{6000}{9.81}(15)\times(0.3) \ln \left(\dfrac{10000}{1-\dfrac{W_{fuel}}{10000}}}\right)\\

\ln \left(\dfrac{10000}{1-\dfrac{W_{fuel}}{10000}}}\right)=1.8167\\\ln \left(\dfrac{1}{10000-W_{fuel}}}\right)=1.8167

Solving this equation, we get,

W_{fuel}=10000\rm\; kg\\

Thus, the amount of kerosene fuel needed for an aircraft weighing 10 metric tons to fly from Boston to Los Angeles, assuming a distance of 5,000 [km] is 10000 kg.

Learn more about the Breguet equation here:

brainly.com/question/15218094

#SPJ1

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2 years ago
The components of your sample mixture are present in trace amounts. Assuming that you will be using GC, what kind of sample intr
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