The enthalpy of the water entering an actual pump is 500 kJ/kg and the enthalpy of the water leaving it is 550 kJ/kg. The pump h
as 98% efficiency, what would have been the enthalpies at the inlet and outlet if the pump was 100% efficient?
1 answer:
Answer:500,551.02
Explanation:
Given
Initial enthaly of pump \left ( h_1\right )=500KJ/kg
Final enthaly of pump \left ( h_2\right )=550KJ/kg
Final enthaly of pump when efficiency is 100%=
Now pump efficiency is 98%
=
0.98=
therefore initial and final enthalpy of pump for 100 % efficiency
initial=500KJ/kg
Final=551.02KJ/kg
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Explanation:
For true Strain:
step 1:
E true = Ln(1 + 0.5 ) = 0.40
Step 2:
E true = Ln(1 + 0.33 ) = 0.29
By single step process:
E true = Ln(1 + 1 ) = 0.69
total strain of step process = 0.40 + 0.29 = 0.69 units
SO TRUE STRAIN IS ADDITIVE.
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