Air at 27°C, 1 atm flows parallel to a flat plate, which is electronically heated. The plate is 0.5 m long in the direction of f
low. The uniform heat flux from the plate to the air is 3,000 W/m². A trip wire placed at the leading edge of the plate ensures that the boundary layer is turbulent over the entire plate. A thermocouple mounted at the trailing edge of the plate records a temperature of 127°C. Consider the following:
a) Determine the local Nusselt number Nuy at the trailing edge of the plate.
b) Calculate the Reynolds number Rex at the trailing edge of the plate.
c) Evaluate the air free stream velocity (m/s).
a) Determine the local Nusselt number Nuy at the trailing edge of the plate.
b) Calculate the Reynolds number Rex at the trailing edge of the plate.
c) Evaluate the air free stream velocity (m/s).
1 answer:
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Answer:
maximum temperature = 1322 k
rate of heat addition = 212 kw
Explanation:
compression ratio = 17
cut off ratio = 1.3
power produced = 140 Kw
state of air at the beginning of the compression = 90 kPa and 578 c
Determine the maximum temperature of air
attached below is the detailed solution
Answer:
Explanation:
Attached is the solution to the question
<h3><u>CSMA/CD Protocol:
</u></h3>
Carrier sensing can transmit the data at anytime only the condition is before sending the data sense carrier if the carrier is free then send the data.
But the problem is the standing at one end of channel, we can’t send the entire carrier. Because of this 2 stations can transmit the data (use the channel) at the same time resulting in collisions.
There are no acknowledgement to detect collisions, It's stations responsibility to detect whether its data is falling into collisions or not.
<u>Example: </u>
, at time t = 10.00 AM, A starts, 10:59:59 AM B starts at time 11:00 AM collision starts.
12:00 AM A will see collisions
Pocket Size to detect the collision.
CSMA/CD is widely used in Ethernet.
<u>Efficiency of CSMA/CD:</u>
- In the previous example we have seen that in worst case
time require to detect a collision.
- There could be many collisions may happen before a successful completion of transmission of a packet.
We are given number of collisions (contentions slots)=4.
Distance = 1km = 1000m