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3 years ago

What body system assists the respiratory system by pulling the rib cage down to allow air toflow in?

Chemistry

2 answers:

victus00 [196]3 years ago

5 0

The body system is the diaphragm

morpeh [17]3 years ago

5 0

Answer:

Diaphragm (a muscle)

Explanation:

the diaphragm moves the allows for more opening as it contracts down. It would most likely be the muacular system since the diaphragm is a muscle.

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What is the valence electron of manganese?

DIA [1.3K]

Answer:

25th electron

Explanation:

the last electron is the valence electron. Assuming it has equal numbers of protons and electrons, then the 25th electron is the valence.

6 0

3 years ago

Read 2 more answers

HELP PLZ ( 10 points )

marta [7]

compressibility - is a measure of the relative volume change of a fluid or solid as a response to a pressure (or mean stress) change. (D)

Flammability - ability of a chemical to burn or ignite, causing fire or combustion. (B)

Heat of Combustion - The amount of heat released per unit mass or unit volume of a substance when the substance is completely burned. (A)

Reactivity - the state or power of being reactive or the degree to which a thing is reactive (C)

Hope this helps!!

4 0

3 years ago

What is the correct equation for water gas

garik1379 [7]

Answer:

Water-gas A mixture of carbon monoxide (CO) and hydrogen (H2) produced by passing steam over red-hot coke using the endothermic reaction C + H2O # CO + H2.

Explanation:

7 0

3 years ago

Be sure to answer all parts. Write the balanced equations corresponding to the following rate expressions: a) rate = − 1 3 Δ[CH4

Alinara [238K]

Answer : The balanced equations will be:

(a) $3CH_4+2H_2O+CO_2\rightarrow 4CH_3OH$

(b) $2N_2O_5\rightarrow 2N_2+5O_2$

(c) $2H_2+2CO_2+O_2\rightarrow 2H_2CO_3$

Explanation :

The general rate of reaction is,

$aA+bB\rightarrow cC+dD$

Rate of reaction : It is defined as the change in the concentration of any one of the reactants or products per unit time.

The expression for rate of reaction will be :

$\text{Rate of disappearance of A}=-\frac{1}{a}\frac{d[A]}{dt}$

$\text{Rate of disappearance of B}=-\frac{1}{b}\frac{d[B]}{dt}$

$\text{Rate of formation of C}=+\frac{1}{c}\frac{d[C]}{dt}$

$\text{Rate of formation of D}=+\frac{1}{d}\frac{d[D]}{dt}$

$Rate=-\frac{1}{a}\frac{d[A]}{dt}=-\frac{1}{b}\frac{d[B]}{dt}=+\frac{1}{c}\frac{d[C]}{dt}=+\frac{1}{d}\frac{d[D]}{dt}$

From this we conclude that,

In the rate of reaction, A and B are the reactants and C and D are the products.

a, b, c and d are the stoichiometric coefficient of A, B, C and D respectively.

The negative sign along with the reactant terms is used simply to show that the concentration of the reactant is decreasing and positive sign along with the product terms is used simply to show that the concentration of the product is increasing.

Now we have to determine the balanced equations corresponding to the following rate expressions.

(a) $Rate=-\frac{1}{3}\frac{d[CH_4]}{dt}=-\frac{1}{2}\frac{d[H_2O]}{dt}=-\frac{d[CO_2]}{dt}=+\frac{1}{4}\frac{d[CH_3OH]}{dt}$

The balanced equations will be:

$3CH_4+2H_2O+CO_2\rightarrow 4CH_3OH$

(b) $Rate=-\frac{1}{2}\frac{d[N_2O_5]}{dt}=+\frac{1}{2}\frac{d[N_2]}{dt}=+\frac{1}{5}\frac{d[O_2]}{dt}$

The balanced equations will be:

$2N_2O_5\rightarrow 2N_2+5O_2$

(c) $Rate=-\frac{1}{2}\frac{d[H_2]}{dt}=-\frac{1}{2}\frac{d[CO_2]}{dt}=-\frac{d[O_2]}{dt}=+\frac{1}{2}\frac{d[H_2CO_3]}{dt}$

The balanced equations will be:

$2H_2+2CO_2+O_2\rightarrow 2H_2CO_3$

4 0

3 years ago

Calculate the wavelength of an electron (m = 9.11 x 10-28 g) moving at 3.66 x 100 m/s. A) 1.81 x 10-10 m B) 2.76 x 10-9 m C) 5.0

inna [77]

Answer:

option e = 1.99 × 10⁻⁶ m

Explanation:

Given data:

Mass of electron = 9.11 × 10⁻²⁸ g or 9.11 × 10⁻³¹ Kg

Velocity = 3.66 × 100 m/s

Wavelength = ?

Solution:

Formula:

λ = h / m. v

λ = wavelength

h = planck's constant

m = mass

v = velocity

Now we will put the values in equation

λ = h / m. v

λ = 6.63 × 10⁻³⁴ Kg. m²/s / 3.66 × 100 m/s . 9.11 × 10⁻³¹ Kg

λ = 6.63 × 10⁻³⁴ Kg. m²/s / 3334.26 × 10⁻³¹ Kg .m/s

λ = 1.99 × 10⁻⁶ m

7 0

3 years ago

Read 2 more answers