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3 years ago

The chemical formula for ethanol is C2H601.How many total atoms are in 30 molecules of ethanol?

1 answer:

3 0

There are two carbon atoms in every ethanol molecule, so there would be 60 carbons all together.

I hope this helped you!

You might be interested in

How do I write 0.03438 m in scientific notation using 3 digits?

Law Incorporation [45]

3.44x10^2
you move the decimal over to get a single digit number with change. The number of times you move the decimal is the number for the 10 power

4 0

2 years ago

Explain why grinding the solid increases the rate of solution.

STALIN [3.7K]

Here, this is what I have. :)

4 0

3 years ago

When a mixture of sulfur and metallic silver is heated, silver sulfide is produced. What mass of silver sulfide is produced from

IgorLugansk [536]

The question is incomplete, here is the complete question.

When a mixture of sulfur and metallic silver is heated, silver sulfide is produced. What mass of silver sulfide is produced from a mixture of 3.0g Ag and 3.0g $S_8$ .

Answer : The mass of silver sulfide is produced from a mixture is 3.44 grams.

Explanation : Given,

Mass of Ag = 3.0 g

Mass of $S_8$ = 3.0 g

Molar mass of Ag = 107.8 g/mole

Molar mass of $S_8$ = 256 g/mole

Molar mass of $Ag_2S$ = 247.8 g/mole

First we have to calculate the moles of Ag and $S_8$ .

$\text{ Moles of }Ag=\frac{\text{ Mass of }Ag}{\text{ Molar mass of }Ag}=\frac{3.0}{107.8g/mole}=0.0278moles$

$\text{ Moles of }S_8=\frac{\text{ Mass of }S_8}{\text{ Molar mass of }S_8}=\frac{3.0g}{256g/mole}=0.0117moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$16Ag(s)+S_8(s)\rightarrow 8Ag_2S(s)$

From the balanced reaction we conclude that

As, 16 mole of $Ag$ react with 1 mole of $S_8$

So, 0.0278 moles of $Ag$ react with $\frac{0.0278}{16}=0.00174$ moles of $S_8$

From this we conclude that, $S_8$ is an excess reagent because the given moles are greater than the required moles and $Ag$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $Ag_2S$

From the reaction, we conclude that

As, 16 mole of $Ag$ react to give 8 mole of $Ag_2S$

So, 0.0278 moles of $Ag$ react to give $\frac{0.0278}{16}\times 8=0.0139$ moles of $Ag_2S$

Now we have to calculate the mass of $Ag_2S$

$\text{ Mass of }Ag_2S=\text{ Moles of }Ag_2S\times \text{ Molar mass of }Ag_2S$

$\text{ Mass of }Ag_2S=(0.0139moles)\times (247.8g/mole)=3.44g$

Therefore, the mass of silver sulfide is produced from a mixture is 3.44 grams.

4 0

3 years ago

Explain, in detail, how you convert grams of one substance to grams of something else. Be specific and include each step

elena-14-01-66 [18.8K]

I will present a simple reaction so we can do this conversion:

2H₂ + O₂ → 2H₂O

We will assume we have 32 g of O₂ and we want to find the amount of water, assuming this reaction goes to completion. We must first convert the initial mass to moles, which we do using the molar mass in units of g/mol. The molar mass of O₂ is 32 g/mol.

32 g O₂ ÷ 32 g/mol = 1 mole O₂.

Now that we have moles of oxygen, we use the molar coefficients to find the ratio of water molecules to oxygen molecules. We can see there are 2 moles of water for every 1 mole of oxygen.

1 moles O₂ x (2 mol H₂O/ 1 mol O₂) = 2 moles H₂O

Now that we have the moles of water, we can convert this amount into grams using the molar mass of water, which is 18 g/mol.

2 moles H₂O x 18 g/mol = 36 g H₂O

Now we have successfully converted the mass of one molecule to the mass of another.

5 0

3 years ago

A 5.00 L flask contains 7.94 g of a gas at STP. What is the molar mass of the gas?

Rashid [163]

Answer: 35.6 g/mol

Explanation: I guessed and got it correct

5 0

2 years ago