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3 years ago

You 12 cupcakes needs 100 grams butter. How much in each cupcake

Mathematics

2 answers:

Natalija [7]3 years ago

6 0

Answer:

The answer is 8.3 repeating. If you round it the answer is 8.

Lesechka [4]3 years ago

5 0

Answer:

8.3... grams in each cupcake

Step-by-step explanation:

you basically divide 100 by 12

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The sum of three consecutive integers is forty -two. find the three numbers

WITCHER [35]

Answer:

13, 14, 15 right?

Step-by-step explanation:

4 0

2 years ago

Can someone please help me with this question asap! greatly appreciated!

dedylja [7]

Answer:

1344 ft^2

Step-by-step explanation:

From the picture we can see that 4w = 3l, which means that l = (4/3)w. Since w = 12 ft, l = (4/3)(12 ft) = 16 ft. Then the total area of the floor is

(length of floor)(width of floor) = (48 ft)(12 ft + 16 ft) = 1344 ft^2

8 0

3 years ago

Find m when 4^(m)*4^(2)=12

miv72 [106K]

Step-by-step explanation:

4^m * 4^2 = 12

4^(m + 2) = 4^(log4 12)

m + 2 = log4 (12)

m = log4 (12) - 2.

4 0

3 years ago

A student believes she can earn between $5200 and $6250 from her summer job. She knows that she will have to buy four new tires

ohaa [14]

Answer:

4180 to 5230$

Step-by-step explanation:

1. Lets find the expenses she has to make -> 4*90+660=1020$(4 new tires + other expenses)

2. As her income is not set strictly we can guess the range she can save(More accurate calculations depends on her strict incomes). We have 5200-1020=4180$(if she gets paid 5200$) and 6250-1020= 5230$(if she gets paid 6250$).

3. So the range of savings vary from 4180 to 5230$$.

4 0

2 years ago

(Uniform) Suppose X follows a continuous uniform distribution from 4 to 11. (a) Write down the PDF of X. (b) Find P(X ≤ 7). Roun

love history [14]

Answer:

a) $f(x)= \frac{1}{11-4}= \frac{1}{7}, 4 \leq x \leq 11$

b) $P(X\leq 7) = F(7) = \frac{7-4}{11-4}= 0.4286$

c) $P(5 < X \leq 7)= F(7) -F(5) = \frac{7-4}{7} -\frac{5-4}{7}= 0.2857$

d) $P(X >5 | X \leq 7)$

And we can find this probability with this formula from the Bayes theorem:

$P(X >5 | X \leq 7)= \frac{P(X>5 \cap X \leq 7)}{P(X \leq 7)}= \frac{P(5$

Step-by-step explanation:

For this case we assume that the random variable X follows this distribution:

$X \sim Unif (a=4, b =11)$

Part a

The probability density function is given by the following expression:

$f(x) = \frac{1}{b-a} , a \leq x \leq b$

$f(x)= \frac{1}{11-4}= \frac{1}{7}, 4 \leq x \leq 11$

Part b

We want this probability:

$P(X \leq 7)$

And we can use the cumulative distribution function given by:

$F(x) = \frac{x-a}{b-a}= \frac{x-4}{11-4}$

And replacing we got:

$P(X\leq 7) = F(7) = \frac{7-4}{11-4}= 0.4286$

Part c

We want this probability:

$P(5 < X \leq 7)$

And we can use the CDF again and we have:

$P(5 < X \leq 7)= F(7) -F(5) = \frac{7-4}{7} -\frac{5-4}{7}= 0.2857$

Part d

We want this conditional probabilty:

$P(X >5 | X \leq 7)$

And we can find this probability with this formula from the Bayes theorem:

$P(X >5 | X \leq 7)= \frac{P(X>5 \cap X \leq 7)}{P(X \leq 7)}= \frac{P(5$

7 0

3 years ago