Answer:
<em>In Point Form:</em> (x,y,z)= (3,6,-1)
<em>In Equation Form:</em> x=3, y=6, z=-1
Step-by-step explanation:
<em>1) Solve for x
</em>
2x+2z=4 (Subtract 2z from both sides)
-2z -2z
2x= 4-2z (Divide 2 from both sides)
/2 /2
x=2-z
<em>2) Substitute 2-z for x in </em>
-x-y-z=-8
-(2-z)-y-z=-8
-2+z-y-z=-8 (Combine Like Terms)
-2-y=-8 (Add 2 to both sides)
+2 +2
-y=-6 (Divide -1 from both sides)
/-1 /-1
y=6
<em>3) Substitute 2-z for x & 6 for y in </em>
-4x+4y+5z+=7
-4(2-z)+4(6)+5z=7 (Get rid of parentheses)
-8+4z+24+5z=7
(Combine Like Terms)
9z+16=7 (Subtract 16 from both sides)
-16 -16
9z+=-9 (Divide 9 from both sides)
/9 /9
z=-1
<em>4) Now find x by substituting -1 for z in </em>
x=2-z
x=2-(-1)
x=2+1
x=3
<em>Therefore the answer is: </em>
<em>In Point Form:</em> (x,y,z)= (3,6,-1)
<em>In Equation Form:</em> x=3, y=6, z=-1