Help please!!!!!!!!!!!!!!!!!!!

A jar of tickets for a drawing contains 22 winning tickets and 63 non-winning tickets. What are the odds against winning in the

Darya [45]

Answer:

B.

Step-by-step explanation:

You have to find the total of tickets which is 85 and find the non-winning tickets which is 63. So, the answer is 63:85.

8 0

3 years ago

Selecting an SUV with a blue exterior

frozen [14]

The answer is straightforward, by the "rule of product":

There are

3×8×2=48

different combinations (distinct possible cars) that can be created.

There 33 choices for body style; 88 choices for exterior colors, and 22 choices of interior color schemes:

Since each of these choices are independent (the choice of body style doesn't depend on exterior or interior color, e.g.) we multiply the number of choices for each quality to obtain: 3×8×2=483×8×2=48 distinct ways to create a car

6 0

2 years ago

The final cost of a bookstore purchase with a $5 coupon in a state that charges 8% sales tax is given by this expression. The va

AnnyKZ [126]

Answer:

B.the total charge before applying sales tax

Step-by-step explanation:

8 0

3 years ago

I bought car of 650,000 and sold it for 520,000. Find the lost Percent ?

harkovskaia [24]

Answer:

20%

Step-by-step explanation:

520,000/650,000 = 0.8

Sold for 80% of original price

Lost percent = 100% - 80%

20%

4 0

2 years ago

The volume of a spherical balloon is increasing at the constant rate of 8 cubic feet per minute. How fast is the radius incresin

OverLord2011 [107]

Answer:

Rate of increase of radius = 0.0064 ft/sec

Rate of increase of surface area = 1.61 $ft^2/sec$

Step-by-step explanation:

Given that:

Rate of change of volume of a spherical balloon = 8 cubic feet per minute

$\dfrac{dV}{dt} = 8 ft^3/min$

Radius, $r$ = 10 feet

To find:

The rate of change of radius at this moment and rate of change of surface area at this moment?

Solution:

First of all, let us have a look at the formula:

$1.\ V = \dfrac{4}{3}\pi r^3\\2.\ A =4\pi r^2$

Now, differentiating the volume and area, we get:

$\dfrac{dV}{dt} = \dfrac{4}{3}\times 3 \pi r^2 \dfrac{dr}{dt}\\\Rightarrow \dfrac{dV}{dt} = 4 \pi r^2 \dfrac{dr}{dt}$

$\dfrac{dA}{dt} = 4\pi \times 2 r \dfrac{dr}{dt}\\\Rightarrow \dfrac{dA}{dt} = 8\pi r \dfrac{dr}{dt}$

$\dfrac{dV}{dt} = 8 = 4\pi r^2 \dfrac{dr}{dt}\\\Rightarrow 8 = 4\times 3.14 \times 10^2 \dfrac{dr}{dt}\\\Rightarrow 2 = 3.14 \times 10^2 \dfrac{dr}{dt}\\\Rightarrow \dfrac{dr}{dt} = 0.0064\ ft/sec$

$\dfrac{dA}{dt} = 8\times \pi \times r \dfrac{dr}{dt}\\\Rightarrow \dfrac{dA}{dt} = 8\times 3.14 \times 10 \times 0.0064\\\Rightarrow \dfrac{dA}{dt} = \bold{1.61 \ ft^2/sec}$

7 0

2 years ago