Okay. To find the answer to this question, let's multiply both fractions together. 3 3/5 as an improper fraction is 18/5 and 1 3/10 as an improper fraction is 13/10. Multiply straight across to get the values. 18/5 * 13/10 is 234/50 or 4 17/25 in mixed number form. Michelle's Snack Shack went through 4 17/25 bottles of mustard.
Split the trapezium into a rectangle and a triangle and work out the areas of them.
4x6=24
(2x4)/2=4
Area of trapezium= 28
There are 2 trapeziums, which makes 56.
The back of the shape is 4x14=56.
The top of the shape is 6x14=84.
The underside of the shape is 8x14=112.
The front rectangle is 14x4.47= 62.58.
As them all together= 56+56+84+112+62.58=370.58.
Total surface area=370.58.
Hope this helps :)
No, 9,156 divisible by 1, 2, 3, 4, 6, 7, 12, 14, 21, 28, 42, 84, 109, 218, 327 , 436, 654 , 763, 1308, 1526, 2289, 3052, 4578, and 9156
All you have to do is combine like terms. 2c and (-c) are like terms (-5b) and (-b) are like terms and a is a term. So, 2c combined with (-c) is C. (-5b) and (-b) combined is (-6b). Since a doesnt need to be combined with anything, you leave it as it is so your answer will then be c - 6b + a (this is the answer assuming that there is a + in front of the a. If there is a - sign, then just change your +a to -a at the end
![[(2-3)^2-5]\cdot4=[(-1)^2-5]\cdot4 \\ \\ =(1-5)\cdot4=-4\cdot4=-16](https://tex.z-dn.net/?f=%5B%282-3%29%5E2-5%5D%5Ccdot4%3D%5B%28-1%29%5E2-5%5D%5Ccdot4%20%5C%5C%20%20%5C%5C%20%3D%281-5%29%5Ccdot4%3D-4%5Ccdot4%3D-16)
![(8-2)^2+\frac{1}{4}[4-3(6-10)]=6^2+\frac{1}{4}[4-3(-4)] \\ \\ =36+\frac{1}{4}[4-(-12)]=36+\frac{1}{4}(4+12)=36+\frac{1}{4}(16) \\ \\ =36+4=40](https://tex.z-dn.net/?f=%288-2%29%5E2%2B%5Cfrac%7B1%7D%7B4%7D%5B4-3%286-10%29%5D%3D6%5E2%2B%5Cfrac%7B1%7D%7B4%7D%5B4-3%28-4%29%5D%20%5C%5C%20%20%5C%5C%20%3D36%2B%5Cfrac%7B1%7D%7B4%7D%5B4-%28-12%29%5D%3D36%2B%5Cfrac%7B1%7D%7B4%7D%284%2B12%29%3D36%2B%5Cfrac%7B1%7D%7B4%7D%2816%29%20%5C%5C%20%20%5C%5C%20%3D36%2B4%3D40)
![3-2[2^3+(-1)^3]=3-2[8+(-1)] \\ \\ =3-2(8-1)=3-2(7)=3-14 \\ \\ -11](https://tex.z-dn.net/?f=3-2%5B2%5E3%2B%28-1%29%5E3%5D%3D3-2%5B8%2B%28-1%29%5D%20%5C%5C%20%20%5C%5C%20%3D3-2%288-1%29%3D3-2%287%29%3D3-14%20%5C%5C%20%20%5C%5C%20-11)
