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STatiana [176]
3 years ago
9

The figure below shows two triangles on the coordinate grid:

Mathematics
1 answer:
madreJ [45]3 years ago
7 0

Answer:

  • Option A

Step-by-step explanation:

A translation 5 units down, followed by a 180-degree counterclockwise rotation about the origin

  • Correct

A translation 5 units down, followed by a 270-degree counterclockwise rotation about the origin

  • Incorrect. It would work with 180-degree rotation.

A 180-degree counterclockwise rotation about the origin, followed by a translation 5 units down

  • Incorrect. It would work with the translation 5 units up.  

A 270-degree counterclockwise rotation about the origin, followed by a translation 5 units down

  • Incorrect.
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The inverse of matrix A = \left[\begin{array}{cc}2&2&1&3\\\end{array}\right] is A^{-1} = \frac{1}{4} \left|\begin{array}{cc}3&-2&-1&2\\\end{array}\right|      

The given matrix is A = \left[\begin{array}{cc}2&2&1&3\\\end{array}\right]

The inverse of a matrix is given by

A^{-1} = \frac{1}{|A|} adjA                   ...(1)

Now, determinant of matrix A is

|A| = \left|\begin{array}{cc}2&2&1&3\\\end{array}\right|

= (3)(2) - (2)(1)

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Now, adjoint A will be

A_{11} = 3

A_{12} = -1

A_{21} = -2

A_{22} = 2

AdjA = \left|\begin{array}{cc}3&-2&-1&2\\\end{array}\right|

Now, substituting the values of |A| and AdjA in equation (1), we get

A^{-1} = \frac{1}{4} \left|\begin{array}{cc}3&-2&-1&2\\\end{array}\right|        

Therefore, A^{-1} = \frac{1}{4} \left|\begin{array}{cc}3&-2&-1&2\\\end{array}\right|      

Know more about Inverse of Matrix: -brainly.com/question/12442362

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Answer:

The answer is C.

Step-by-step explanation:

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