Answer:
Now we just take square root on both sides of the interval and we got:
And the best option would be:
A. 2.2 < σ < 2.8
Step-by-step explanation:
Information provided
represent the sample mean
population mean
s=2.4 represent the sample standard deviation
n=83 represent the sample size
Confidence interval
The confidence interval for the population variance is given by the following formula:
The degrees of freedom are given by:
The Confidence is given by 0.90 or 90%, the value of 
and 
, the critical values for this case are:
And replacing into the formula for the interval we got:
Now we just take square root on both sides of the interval and we got:
And the best option would be:
A. 2.2 < σ < 2.8
Answer:
-6
Step-by-step explanation:
Some nasty order of operations coming up.
Firstly, deal with that squared:
-12 / 3 * (-8 + 16 - 6) + 2
Simplify the bracket:
-12 / 3 * 2 + 2
Simplify -12 / 3:
-4 * 2 + 2
Simplify -4 * 2:
-8 + 2
Simplify:
-6
1.For each of the following, give the name of an element from Period 4 (potassium to krypton), which matches the description.
Elements may be used once, more than once or not all.. Single line text.
(1 Point)
an element that reacts with water to produce a lilac flame
2.For each of the following, give the name of an element from Period 4 (potassium to krypton), which matches the description.
Elements may be used once, more than once or not all.. Single line text.
(1 Point)
an element used as an inert atmosphere
3.For each of the following, give the name of an element from Period 4 (potassium to krypton), which matches the description.
Elements may be used once, more than once or not all.. Single line text.
(1 Point)
an element that has a valency of 3
4.Write a balanced chemical equation for the reaction between potassium and water. (Non-anonymous question). .
(1 Point)
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5.For each of the following, give the name of an element from Period 4 (potassium to krypton), which matches the description.
Elements may be used once, more than once or not all.. Single line text.
(1 Point)
an element with a fixed valency of 2 that not is not in group 2
HELP
This problem mean you have to find the point that the Domain and Range is suit (I'm sorry English is my second language)
Example:
1) G ; 2) Y
If you want me to do the rest of it tell me Okay ^^
Area of a circle= πr²
Data:
diameter=11 in
ratius=diameter/2=11 in/2=5.5 in
Area of this circular plate=π(5.5 in)²=30.25π in²=30.25 * 3.141592... in²≈
≈95.0 in².
answer : c 95.0 in²
