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iogann1982 [59]
2 years ago
6

Sketch the line passing through the pair of points and identify the line as having a positive slope, a negative slope, a zero sl

ope, or an undefined slope. (6,2) and (1,2)​
Mathematics
1 answer:
scoundrel [369]2 years ago
5 0

Answer:

line will be horizontal running through (0,2)

Step-by-step explanation:

6,2
1,2
2-2/1-6 = 0/-5 = 0 slope. 2 = 0x6+b, 2=b. line will be y=b , y=2.

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What is the answer to this problem 0.05n+0.10(2n)=9.25
kolbaska11 [484]

Answer: n=37

Step-by-step explanation:

0.05n+0.10x2n=9.25

0.25n=9.25

n=9.25/0.25

n=37

6 0
3 years ago
Write a quadratic relation in the form y = ax2 + bx + c with roots 4 and - 3 and
pochemuha

Answer:

y =  2*x^2 - 2*x - 24

Step-by-step explanation:

If we have a quadratic function with roots a and b, we can write the equation for that function as:

y = f(x) = A*(x - a)*(x - b)

Where A is the leading coefficient.

In this case, we know that the roots are: 4 and -3

Then the function will be something like:

f(x) = A*(x - 4)*(x - (-3) )

f(x) = A*(x - 4)*(x + 3)

Now we need to determine the value of A.

We also know that the graph of the function passes through the point (3, -12)

This means that:

f(3) = -12

Then:

-12 = A*(3 - 4)*(3 + 3)

-12 = A*(-1)*(6)

-12 = A*(-6)

-12/-6 = A

2 = A

Then the equation is:

y = f(x) = 2*(x - 4)*(x + 3)

Now we need to write this in standard form, so we just need to expand the equation:

y = f(x) = 2*(x^2 + x*3 - x*4 - 4*3)

y = f(x) = 2*(x^2 - x - 12)

y = f(x) = 2*x^2 - 2*x - 24

Then the relation is:

y =  2*x^2 - 2*x - 24

4 0
3 years ago
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Step-by-step explanation:

(f(x) g(x)) = (x^{2} -4)(x-2)

              = x^3-2x^2-4x+8  via FOIL

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3 years ago
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Answer:

Angle 1 is 135 degree

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3 years ago
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Answer:

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Step-by-step explanation:

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