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Brrunno [24]
3 years ago
14

5) February is a busy time at Charlie's Chocolate Shoppe! During the week before Valentine's Day, Charlie advertises that his ch

ocolates will be selling for $1.80 a piece (instead of the usual $2.00 each). The fixed costs to run the Chocolate Shoppe total $450 for the week, and he estimates that each chocolate costs about $0.60 to produce. Charlie estimates that he can produce up to 3,000 chocolates in one week. a) Write a function, C(n), to represent Charlie's total costs for the week if he makes n chocolates b) Write a function. R(n), to represent the revenue from the sale of n chocolates during the week before Valentine's Day. c) Write a function. P(n), that represents Charlie's profit from selling n chocolates during the week before Valentine's Day. Show complete work to find the function.​
Mathematics
1 answer:
Zolol [24]3 years ago
3 0

Answer:

a) C(n) = 450+0.60n where n

b) R(n) = 1.80n where n

c) P(n) = - 450 +1.20n

Step-by-step explanation:

Sale price of chocolates = $1.80 per chocolate

Fixed cost for the Chocolate Shoppe per week = $450

Cost to produce one chocolate = $0.60

Cost to produce n chocolates = $0.60\times n

a) Cost function to represent the total cost for the production of n chocolates :

C(n) = 450+0.60n where n

b) Revenue function to represent the revenue from the sale of n chocolates:

R(n) = 1.80n where n

c) Profit function to represent Charlie's profit from selling n chocolates:

Profit is nothing but revenue minus sales.

P(n) = R(n) - C(n) \\P(n) = 1.80n - 450 -0.60n\\P(n) = - 450 +1.20n

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Lina20 [59]

Hey there! I'm happy to help!

First, let's add the hundreds and the tens.

300+80=380

We see that there is nothing in the ones place, so we keep our ones place 0 and we move onto adding the tenths.

380+0.9=380.9

We add the hundredths.

380.9+0.06=380.96

And finally, we add the thousandths.

380.96+0.001=380.961

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Have a wonderful day! :D

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Step-by-step explanation:

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