Listed below are the 35 members of the Metro Toledo Automobile Dealers Association. We would like to estimate the mean revenue f
1 answer:
Answer:
Following are the solution to the given question:
Step-by-step explanation:
There will be 35 members of the Toledo Automotive Metro from such reports
The Organization of Distributors. The membership is sequentially numbered between 00 and 34.
The five traders selected a random sample as follows:
The decision should be made in 00 and 34.
In this the remaining numbers 39, 94,. . . . .67 were not chosen because it is beyond the ranges that are 00-34.
The samples contain 34, 32, 25, 13, and 19 distributors.
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The force in the rod when the temperature is 150 °F is 718.72 pounds-force.
<h3>How to determine the resulting the resulting force due to mechanical and thermal deformation</h3>Let suppose that rod experiments a <em>quasi-static</em> deformation and that both springs have a <em>linear</em> behavior, that is, force (), in pounds-force, is directly proportional to deformation. Then, the elongation of the rod due to <em>temperature</em> increase creates a <em>spring</em> deformation additional to that associated with <em>mechanical</em> contact.
Given simmetry considerations, we derive an expression for the <em>spring</em> force (), in pounds-force, as a sum of mechanical and thermal effects by principle of superposition:
(1)
Where:
- Spring constant, in pounds-force per inch.
- Spring deformation, in inches.
- Rod elongation, in inches.
The <em>rod</em> elongation is described by the following <em>thermal</em> dilatation formula:
(2)
Where:
- Coefficient of linear expansion, in
.
- Initial length of the rod, in inches.
- Initial temperature, in degrees Fahrenheit.
- Final temperature, in degrees Fahrenheit.
If we know ,
,
,
,
and
, then the force in the rod at final temperature is:
The force in the rod when the temperature is 150 °F is 718.72 pounds-force.
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