This is probably the answer I’m not 100% sure
Through trial and error:
(7x-6)(3x-2)
Usually it works best to test out a number of possibilities :)
A because 2b is b times 2 and 235 is bigger
Answer: Ix - 4I ≤ 4
Step-by-step explanation:
You can see a black dot in the zero, and a black dot in the 8.
So those are the extremes of our set and are included in the set of solutions, we have that the set is defined by:
0 ≤ x ≤ 8.
Now we want to construct an absolute value equation such that the set {0 ≤ x ≤ 8} is the set of solutions.
The first step is to find the middle value of that set:
The middle value is equal to half of the difference between the extremes:
m = (8 - 0)/2 = 4.
Now we know the middle point, so we can write the equation:
Ix - mI ≤ m
m = 4
Ix - 4I ≤ 4
That is our inequality.
Where the "equal" part of ≤ is for the values x = 0 and x = 8.
We have the following expression:
(27a ^ 3-1) / (9a ^ 2-6a + 1)
Rewriting we have:
(27a ^ 3-1) / (9a ^ 2-6a + 1)
(27a ^ 3-1) / ((3a-1) * (3a-1))
We exclude the values that make the denominator zero:
3a-1 = 0
a = 1/3
Answer:
a valid exclusion for the algebraic fraction is:
c. a ≠ 1/3
