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riadik2000 [5.3K]
3 years ago
13

What's the difference between -1/2 and 1/6

Mathematics
1 answer:
horsena [70]3 years ago
4 0

Answer: -4/6 or -2/3

Step-by-step explanation:

First, you find a common denominator among the fractions, which would be 6.

Convert -1/2 to have 6 as its denominator.

-1/2* 3/3 = -3/6

And then subtract them.

-3/6 - 1/6 = -4/6

-4/6 simplified is -2/3

When you subtract a positive number from a negative number, you are adding their absolute values.

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*** 10 points**** if you help me
blsea [12.9K]

Answer:

h squared is 65 but h is 8.06

Step-by-step explanation:

use the pythagorean theorem

7^2+4^2=

49+16= 65

square root of 65 is 8.06

hope this helps

8 0
3 years ago
To inspect manufacturing processes, companies typically examine samples of parts for deficiencies. One company that manufactures
marishachu [46]

Answer:

a. All measures exist

b. The Mean and the mode

c. Positively skewed

d. The mean and the median

Step-by-step explanation:

a. The frequencies of the data are;

1       2

2      4

3       1

5       2

6       3

9        1

11        1

14        1

15       1

18       1

The formula for mode is given as follows;

The mean = 108/17 = 6.35

The median of 1 1 2 2 2 2 3 5 5 6 6 6 9 11 14 15 18 = (n + 1)/2th term = 9th term  

∴ The median = 5

The mode = 3×Median - 2 × Mean = 15 - 2 × 6.35 = 2.29

Hence all exist

The answer is none theses measures

b. Whereby 18 is replaced by 39 the mean will be then be

(108 + 39 - 18)/17 = 7.59

The median, which is the 9th term remain the same;

Hence only the mean and mode will be affected

c. Since more values are concentrated on the left side of the data distribution, the distribution is positively skewed

d. The largest measurement = 18 the 17th term

Removal will give

Mean = (108 - 18)/16 = 5.625 Mean changes

Median = (16 + 1)/2 th term = 8.5th term = 5 The median remains the same

The mode = 3(Mean - Median) changes

Therefore, the mean and the median will be changed.

6 0
3 years ago
A student carried out an experiment to determine the amount of vitamin C in a tablet sample. He performed 5 trials to produce th
ivolga24 [154]

Answer:

There is not enough evidence to support the claim that the amount of vitamin C in a tablet sample is different from 500 mg.

P-value = 0.166.

Step-by-step explanation:

We start by calculating the mean and standard deviation of the sample:

M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{5}(490+502+505+495+492)\\\\\\M=\dfrac{2484}{5}\\\\\\M=496.8\\\\\\s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{4}((490-496.8)^2+(502-496.8)^2+(505-496.8)^2+(495-496.8)^2+(492-496.8)^2)}\\\\\\s=\sqrt{\dfrac{166.8}{4}}\\\\\\s=\sqrt{41.7}=6.5\\\\\\

Then, we can perform the hypothesis t-test for the mean.

The claim is that the amount of vitamin C in a tablet sample is different from 500 mg.

Then, the null and alternative hypothesis are:

H_0: \mu=500\\\\H_a:\mu< 500

The significance level is 0.05.

The sample has a size n=5.

The sample mean is M=496.8.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=6.5.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{6.5}{\sqrt{5}}=2.907

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{496.8-500}{2.907}=\dfrac{-3.2}{2.907}=-1.1

The degrees of freedom for this sample size are:

df=n-1=5-1=4

This test is a left-tailed test, with 4 degrees of freedom and t=-1.1, so the P-value for this test is calculated as (using a t-table):

\text{P-value}=P(t

As the P-value (0.166) is bigger than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the amount of vitamin C in a tablet sample is different from 500 mg.

4 0
3 years ago
RIGHT ANSWER WILL BE MARK BRAINLIEST
nirvana33 [79]
...............the answer is D
6 0
3 years ago
Read 2 more answers
In our Solar system six of the eight planets have moons what percentage of the planets have moons
Vladimir79 [104]
75%
you just divide 6/8
7 0
3 years ago
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