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3 years ago

Please help me solve this. :)

Mathematics

1 answer:

Aloiza [94]3 years ago

6 0

Answer:

Step-by-step explanation:

Given problem:

x² - y²

x+ y = 10

x - y = 4

Solution:

Using the concept of differences of two squares;

x² - y² = (x + y)(x - y)

So;

x² - y² = 10 x 4 = 40

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Solve for x. (e^x-e^-x)/((e^x+e^-x)=t

Sergio [31]

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3 years ago

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What is the area of a triangle with side lengths 13-14-15?

Novosadov [1.4K]

84. Area of a triangle is (base x height) / 2

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3 years ago

Given f(x) = x ^ 2 - 6x + 8 and g(x) = x + 2 solve f(x) = g(x) . Use the tables below to help you, but please explain how you ca

Travka [436]

Answer:

see explanation

Step-by-step explanation:

Given

f(x) = x² - 6x + 8 and g(x) = x + 2

To solve f(x) = g(x), equate the right sides, that is

x² - 6x + 8 = x + 2 ← subtract x + 2 from both sides

x² - 7x + 6 = 0 ← in standard form

(x - 1)(x - 6) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 1 = 0 ⇒ x = 1

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These solutions can be verified from the tables, that is

f(x) = g(x) = 3 ← when x = 1

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3 years ago

Which of the two solids below are similar ?

Pachacha [2.7K]

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Step-by-step explanation:

By definition, two solids are similar if their corresponding sides are in the same ratio.

Knowing this, let's find which solids are similar:

Corresponding sides ratio of solids I and II:

$\frac{3}{2}=\frac{2}{\frac{4}{3}}=\frac{5}{\frac{10}{3}}$

$\frac{3}{2}=\frac{3}{2}=\frac{3}{2}$

Corresponding sides ratio of solids I and III:

$\frac{3}{\frac{9}{2}}=\frac{2}{3}=\frac{5}{8}$

$\frac{2}{3}=\frac{2}{3}=\frac{5}{8}$

Corresponding sides ratio of solids II and III:

$\frac{2}{\frac{9}{2}}=\frac{\frac{4}{3}}{3}}=\frac{\frac{10}{3}}{8}}$

$\frac{4}{9}=\frac{4}{9}=\frac{5}{12}$

You can observe that the solids I and II are similar.

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2 years ago

Which of the following is true?

mart [117]

<span>-6.175 is an irrational number: FALSE. -6175/1000 is a rational number.

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Square root 2 is an integer. FALSE. Definitely not.

</span>

8 0

2 years ago

Please help me solve this. :)​

Please help me solve this. :)