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poizon [28]
3 years ago
13

Find the value of the

Mathematics
1 answer:
Nataliya [291]3 years ago
5 0

Answer:

a.

<u>cos θ = 2/5, tan θ = ?</u>

  • tan θ = sin θ / cos θ
  • tan θ = √sin² θ / (2/5)
  • tan θ= 5√(1 - cos²θ) / 2
  • tan θ = 5√(1 - 4/25) / 2
  • tan θ = 5√(21/25) / 2
  • tan θ = √21 / 2

b.

<u>cosec θ = 7/3, cos θ = ?</u>

  • cosec θ =  1/ sin θ
  • cosec θ = 1/ √(1 - cos²θ)
  • √(1 - cos²θ) = 1 / cosec θ
  • 1 - cos²θ = (1 / (7/3))²
  • cos²θ = 1 - 9 / 49
  • cos²θ = 40/49
  • cos θ = √40/49
  • cos θ = 2√10/7

c.

<u>cot θ = 4/3, sec θ = ?</u>

  • cot  θ = cos θ / sin θ
  • cos θ = cot θ * sin θ
  • cos θ = 4/3 * √(1 - cos²θ)
  • 9cos²θ = 16(1 - cos²θ)
  • 25cos²θ = 16
  • cos²θ = 16/25
  • cos θ √16/25
  • cos θ = 4/5
  • sec θ = 1/ cos θ
  • sec θ = 1/ (4/5)
  • sec θ = 5/4

d.

<u>tan θ = 3, cosec θ = ?</u>

  • sin²θ + cos²θ = 1
  • 1 + cos²θ/sin²θ = 1/ sin²θ
  • 1 + 1/tan²θ = cosec²θ
  • 1 + 1/9 = cosec²θ
  • cosec²θ = 10/9
  • cosec θ = √(10/9)
  • cosec θ = √10 / 3
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