Answer:
m=-44
Explanation: distribute the negative and add -1/4 to m and then take the 5 away from 16 and then multiply both sides
10. GCF is 3
11. GCF is 4
12. GCF is 16
13. That the numbers are prime
:)
The answer is 14/3 or 4 and 2 thirds
Answer:
Length = 45.37 in
Width = 30.56 in
Step-by-step explanation:
Let the width of the picture be 'w' inches.
Given:
Perimeter of the picture is, ![P=106.5\ in](https://tex.z-dn.net/?f=P%3D106.5%5C%20in)
Length is 15.75 inches shorter than twice the width. So, length is:
![l=2w-15.75](https://tex.z-dn.net/?f=l%3D2w-15.75)
Now, we know that the perimeter of a rectangular shape is given as the sum of all of its side. So, the picture is also of rectangular shape and hence the perimeter is given as:
![P=2l+2w](https://tex.z-dn.net/?f=P%3D2l%2B2w)
Plug in the values of 'l' and 'P' and solve for 'w'. This gives,
![106.5=2w-15.75+2w\\106.5=4w-15.75\\106.5+15.75=4w\\4w=122.25\\w=\frac{122.25}{4}=30.56\ in](https://tex.z-dn.net/?f=106.5%3D2w-15.75%2B2w%5C%5C106.5%3D4w-15.75%5C%5C106.5%2B15.75%3D4w%5C%5C4w%3D122.25%5C%5Cw%3D%5Cfrac%7B122.25%7D%7B4%7D%3D30.56%5C%20in)
Therefore, the width of the rectangular picture is 30.56 inches.
Length of the picture is, ![l=2(30.56)-15.75=61.12-15.75=45.37\ in](https://tex.z-dn.net/?f=l%3D2%2830.56%29-15.75%3D61.12-15.75%3D45.37%5C%20in)
So, length of the picture is 45.37 inches and width is 30.56 inches.
24+24+11+11=60?
48+22=60?
60=60?
:D You're correct