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2 years ago

Elena has some bottles of water that each holds 17 fluid ounces.How much water is in 51 bottles.

Mathematics

2 answers:

sineoko [7]2 years ago

8 0

51 bottles 17 fl. oz.
--------------- * -------------- = 867 fluid ounces of water.
1 1 bottle

Kitty [74]2 years ago

3 0

Answer: 867

because
if 1 bottle is 17 fluid ounces
than if you multiply 51 bottels
with 17 fluid ounces it gives you
867 fluid ounces.

51 * 17 = 867

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If I buy a stereo for $245 and this includes GST of 10%, what is the pre-GST price?

Ivan

Answer: $222.73

===========================================

Work Shown:

x = pre-GST price

10% of x = 0.10x = tax amount

x + 0.10x = 1.10x = post-GST price = 245

1.10x = 245

x = 245/1.10

x = 222.7272 approximately

x = 222.73 is the price before tax.

------------

Check:

10% of 222.73 = 0.10*222.73 = 22.273 = 22.27

The tax amount ($22.27) is added to the pre-GST price to get

22.27+222.73 = 245

which matches the post-GST price mentioned.

The answer is confirmed.

Or another way to confirm the answer is to calculate this

1.10*222.73 = 245.003 = 245

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Answer:

Step-by-step explanation:

Estimating a sum by rounding to get the best estimate is the goal of this lesson. Notice that we try to estimate. We don't need to have an exact answer!

Notice that for numbers with two digits, there can only be one estimate because you can only round to the tens place.

Estimate the following sums: 36 + 21, 74 + 15, and 85 + 24

36 + 21 = 40 + 20 = 60

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Is 28,164 smaller or bigger than 281,644?

nevsk [136]

Smaller because off the number value and places.

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2 years ago

If the numbers 4, 5 and 6 are each used exactly once to replace the letters in the expression A ( B − C ), what is the least pos

guapka [62]

Answer:

The least possible result is -10.

Step-by-step explanation:

Given the numbers 4, 5 and 6 are to be chosen one of the letters A, B or C.

First of all,

Let A = 4, B = 5 and C = 6

$A(B-C) = 4 \times (5-6) = 4 \times -1 = -4$

Let A = 4, B = 6 and C = 5

$A(B-C) = 4 \times (6-5) = 4 \times 1 = 4$

Let A = 5, B =4 and C = 6

$A(B-C) = 5 \times (4-6) = 5 \times -2 = -10$

Let A = 5, B = 6 and C = 4

$A(B-C) = 4 \times (6-4) = 4 \times 2 = 8$

Let A = 6, B = 4 and C = 5

$A(B-C) = 6 \times (4-5) = 6 \times -1 = -6$

Let A = 6, B = 5 and C = 4

$A(B-C) = 6 \times (6-5) = 6 \times 1 = 6$

Summarizing the above values in the form of a table:

$\begin{center}\begin{tabular}{ c c c c}A & B & C & A(B-C)\\ 4 & 5 & 6 & -4\\ 4 & 6 & 5 & 4\\ 5 & 4 & 6 & -10\\ 5 & 6 & 4 & 10\\ 6 & 4 & 5 & -6\\ 6 & 5 & 4 & 6\end{tabular}\end{center}$

So, the least possible result is -10.

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3 years ago