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aksik [14]
3 years ago
7

Let's see who can answer this;)​

Mathematics
1 answer:
oksian1 [2.3K]3 years ago
8 0

Answer:

0.88, 8.08, 8.80

2.4, 2.49, 3.71, 3.87, 4.92

Step-by-step explanation:

By logic.

Or mathematically speaking, if x is greater than y, means that x-y > 0.

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If 48X^2,64x^4 ,x 36x^2 are in proportion , find the value of x​
SCORPION-xisa [38]

Answer:

The value of x = 27

Step-by-step explanation:

Given:

48x² : 64x⁴ ::: x : 36x²

Find:

The value of x

Computation:

(a)(d) = (b)(c)

(48x²)(36x²) = (64x⁴)(x)

(1,728x⁴) = (64x⁵)

x = 27

The value of x = 27

7 0
3 years ago
Solve for x: 3 < x + 3 < 6
Vesnalui [34]
The answer is D. 0>3
6 0
3 years ago
Which set of ordered pairs represents a function?
finlep [7]

Answer:

{(-1,0),(-8, 9), (7,0), (1,3)}

Step-by-step explanation:

number 3 is the only one with no colliding outputs.

6 0
3 years ago
The sum of a number times 7 and 30 is at most -24
NARA [144]

Answer:

x•7+30=-24

Step-by-step explanation:

This might be your answer, if not please comment and let me know what it really was! Thanks!

7 0
3 years ago
B is the midpoint of AC and E' is the midpoint of BD. If A(-9,-4), C(-1, 6), and E(-4,-3), find the coordinates of D.
Ipatiy [6.2K]
The coordinates for D are (-4, -7)

First we must locate point B as it is vital to finding the midpoint of BD. To do this, we take the average of the endpoints AC since B is its midpoint. 

x values = -9 + 1 = -8
Then divide by 2 for the average -8/2 = -4

y values = -4 + 6 = 2
Then divide by 2 for the average 2/2 = 1

Therefore B must be (-4, 1)

Now we know the values of E must be the average of B and D. So we can write equations for each coordinate since we know they are averages. 

x - values = (Bx + Dx)/2 = Ex
(-4 + Dx)/2 = -4 ---> multiply both sides by 2
-4 + Dx = -8 ---> add -4 to both sides
Dx = -4

y - values = (By + Dy)/2 = Ey
(1 + Dy)/2 = -3 ---> multiply both sides by 2
1 + Dy = -6 ---> subtract 1 from both side
Dy = -7

So the coordinates for D must be (-4, -7)
5 0
3 years ago
Read 2 more answers
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