Example answer number one
Hello!
A half-life is the amount of time it takes half of an element to decay. For example, after one of carbon's half-life, half of carbon would've decayed.
Now, we can calculate how much has decayed if 5 half lives have passed.
1 -> 50% (1) -> 25% (2) -> 12.5% (3) -> 6.25% (4) -> 3.125% (5)
Therefore, there would be 3.125% left of iodine. However, your question is asking what percent has decayed. Therefore, subtract 3.125 from 100% to get your final answer.
100 - 3.125 = 96.875
Therefore, your final answer is 96.875% of iodine has decayed if 5 half lives have passed.
Hope this helps!
Explanation:
In a covalent bond, there is sharing of the donated electron by two atomic species having very small electronegative differences between them.
Oxidation is the loss of electrons by a specie and it usually lead to an increase in oxidation number.
Reduction is the gain of electrons by a specie. It leads to a lower oxidation number.
Since there is no actual loss of gain of electrons in a covalent body, the electronegativiy is at work.
Electronegativity is the ability of a specie to draw the shared electrons more to itself in a covalent bond.
- Between two atoms bonded covalently, the more electronegative specie draws the electrons closer.
- This leaves a partial negative charge on it.
- The other electron then becomes partially positively charged.
- We can then say, the more electronegative specie undergoes reduction.
- The less electronegative one undergoes oxidation.
learn more:
Covalent bond brainly.com/question/3064597
Oxidation and reduction brainly.com/question/2278247
#learnwithBrainly
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➷ The correct answers would be:
phosphate molecule, nitrogenous base and deoxyribose sugar.
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