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AURORKA [14]
3 years ago
6

Can someone help me with this math homework please!

Mathematics
1 answer:
Korvikt [17]3 years ago
5 0

Answer:

Last answer.

Step-by-step explanation:

What I do is divide the terms by the previous terms, and if they all equal 1.5, that is your answer.

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I got 2d^4-2d^2-5/d^2

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What is the area of the rhombus in simplest radical form? The figure is not drawn to scale.
Tanya [424]

The area of the Rhombus is 162√3 sq.unit , Option A is the correct answer.

<h3>What is a Rhombus ?</h3>

A rhombus is a polygon , which has four equal sides , its diagonal bisect each other at 90 degree.

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tan 60 = x / 9

x = 9 tan 60

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Area of the Rhombus = (d1 * d2 /2 )

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6 0
2 years ago
A pencil consists of a cone stacked on top of a cylinder. The diameter of the cylindrical base of the pencil is 10 mm and the he
11Alexandr11 [23.1K]

Answer:

790π

Step-by-step explanation:

We are given;

Diameter of cylinder;d = 10 mm

So, radius;r = 10/2 = 5 mm

Height of cylinder;h = 70mm

Surface area of cylinder is given by the formula; S.A = 2πr² + 2πrh

Plugging in the relevant values, we have;S.A = 2π(5)² + 2π(5)(70)

S.A = 50π + 700π

S.A = 750π

Now, because one base of the cylinder is hidden as the cone is stacked on that face, we will deduct the area of that base face;

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For the cone,

Height;h = 12mm

Since this is stacked directly on the cylinder, it will have the same radius. Thus; radius;r = 5mm

Now,formula for surface area of cone is;

S.A = πr² + πrL

Where L is slant height.

We can use pythagoras theorem to get L.

So, L² = r² + h²

L = √r² + h²

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L = √(25 + 144)

L = √169

L = 13

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Similar to what was done to the Cylinder, since the circular base of the cone is stacked on the cylinder, we will deduct the surface area of that base as it is hidden.

So, S.A is now = 90π - π(5)²

= 90π - 25π = 65π

Thus,total surface area of the pencil = 725π + 65π = 790π

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Answer:

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