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Nikolay [14]
2 years ago
9

Shelly is tying to improve her running time for track race. She ran the first race 43.13 seconds. Her time was 43.1 seconds in t

he second race and 43.07 seconds in the third race. If this patteren continues, what will Shelly's time be in the fourth race?
Mathematics
1 answer:
grandymaker [24]2 years ago
3 0

Answer:

42.77

Step-by-step explanation:

The pattern is taking away 0.3. 43.07 minus 0.3 equals 42.77

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Hi, Could anyone help me with my homework
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Answer:

\hookrightarrow \sf  x^6+24x^5+240x^4+1280x^3+3840x^2+6144x+4096

solving steps:

\rightarrow \sf (x + 4)^6

\bold{rewrite \ the \ following}

\rightarrow \sf (x + 4)^2   (x + 4)^2   (x + 4)^2

\bold {formula \ used : \sf  (x+a)^2 = (x^2 + 2xa + a^2)}

\rightarrow \sf (x^2 + 8x+16)    (x^2 + 8x+16)    (x^2 + 8x+16)

\bold{simplify \ by  \ removing \ parenthesis}

\rightarrow \sf (x^4 +8x^3 + 16x^2 + 8x^3 +64x^2 + 128x+16x^2+128x+256 ) (x^2 + 8x+16)

\bold{basic \ addition \ of \ integers }

\rightarrow \sf (x^4+16x^3+96x^2+256x+256) (x^2 + 8x+16)

\bold{remove \ parenthesis}

\rightarrow \sf (x^6 + 16x^5 + 96x^4 + 256x^3 + 256x^2 + 8x^6 + 128x^4 + 768x^3 + 2048x^2 + 2048 + 16x^4 + 256x^3 + 1536x^2 + 4096x + 4096)

\bold {final \ answer:}

\rightarrow \sf  x^6+24x^5+240x^4+1280x^3+3840x^2+6144x+4096

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= 40/3 /8/3= 5

Hope that helps!


3 0
3 years ago
Read 2 more answers
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