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vova2212 [387]
3 years ago
12

Is 55 810 a multiple of 10

Mathematics
2 answers:
worty [1.4K]3 years ago
8 0

Answer:

Yes

Step-by-step explanation:

Any number that ends with a zero is a multiple of 10

Rzqust [24]3 years ago
6 0
Yes 10 *5581 = 55810
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Can someone plz help me with this one problem plzzzzz I’m marking brainliest!!!
Andre45 [30]
2=6
4=8
6=10
8=12
I added +4 for each
8 0
2 years ago
Select "Yes" or "No" to indicate whether the ordered pair is on the graph of the function f(x)=−25^x+1.
KengaRu [80]
<span>(1,625) No (0,-25) No (-1,-1) No Think about what an integer exponent means for an negative base and you'll understand this problem. For instance the powers of -25 would be -25^1 = -25 -25^2 = (-25) * (-25) = 625 -25^3 = (-25)*(-25)*(-25) = -15625 and so on, giving 390625, -9765625, 244140625, etc. But that's a different subject. For the ordered pairs given, let's check them out. (1,625) -25^1 + 1 = -25 + 1 = -24. And -24 is not equal to 625, so "No". (0,-25) -25^0 + 1 = 1 +1 = 2. Note: Any real number other than 0 raised to the 0th power is 1. And 2 is not equal to -25, so "No". (-1,-1) -25^(-1) + 1 = 1/(-25^1) + 1 = 1/-25 + 1 = 24/25. And 24/25 is not equal to -1, so also "No".</span>
3 0
3 years ago
Read 2 more answers
Apparently Nobody is able to answer this question. You can search it up but I've tried that already, still no answer.
damaskus [11]

Answer:

if it is odd then multiply it by 3 and add 1, and if it is even, divide it by 2. Then repeat this process as long as you can.

Step-by-step explanation:

hope dis helped:)

8 0
1 year ago
Activity 1.1 Simplify Me Simplify by removing perfect nth powers: 1. √20 2. √300 3. √128 3 4. √ 5 3 5. √50 3
LekaFEV [45]

Answer:

(a)\ \sqrt{20}=2\sqrt{5}

(b)\ \sqrt{300} = 10 \sqrt{3}

(c)\ \sqrt{128} = 8 \sqrt{2}

Step-by-step explanation:

Required

Simplify

(a)\ \sqrt{20}

Express 20 as 4 * 5

\sqrt{20}=\sqrt{4 * 5}

Split

\sqrt{20}=\sqrt{4} * \sqrt{5}

This gives:

\sqrt{20}=2 * \sqrt{5}

\sqrt{20}=2\sqrt{5}

(b)\ \sqrt{300

Express as 100 * 3

\sqrt{300} = \sqrt{100} * \sqrt{3}

This gives:

\sqrt{300} = 10 * \sqrt{3}

\sqrt{300} = 10 \sqrt{3}

(c)\ \sqrt{128}

Express as 64 * 2

\sqrt{128} = \sqrt{64*2}

Split

\sqrt{128} = \sqrt{64} * \sqrt{2}

\sqrt{128} = 8 * \sqrt{2}

\sqrt{128} = 8 \sqrt{2}

<em></em>

<em>Questions 4 and 5 are not clear</em>

<em>Follow the steps in 1 - 3 to solve 4 and 5</em>

7 0
2 years ago
7. A sales girl is paid Rs 5,000 per month as salary and a 4 commission of % on total sales. If she receives Rs 5,192 at the end
kari74 [83]

Answer:

Sh 4800

Step-by-step explanation:

5192 - 5000 = 192 ( which is the total commission)

4% = 192

100%=? ( so we get the total sales)

100*192/4 = 4800 ( which is the total sales )

5 0
2 years ago
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