Which point of intersection is the solution to the equations y = 2/5x-1/2 and y = -1/3x + 2/3?
1 answer:
You might be interested in
Answer: choice B) yes; only one range value exists for each domain value
---------------------------------
---------------------------------
Explanation:
The inputs are x = -3, x = -1, x = 1, x = 5. They are the first coordinate listed of each point. We don't have any x values repeating so this means we have a function. Each input leads to exactly one output which is what choice B is stating. The domain is the set of allowed inputs, or x values. The range is the set of possible y outputs.
If we had something like (1,2) and (1,5) then the input x = 1 leads to more than one output (y = 2 and y = 5). This example means we don't have a function
If you graph the points (-3, -2), (-1,0), (1,0) and (5,-2) as shown in the attached image, then you'll notice that it is impossible to pass a single line through more than one point. Therefore this graph passes the vertical line test visually proving we have a function.
Going back to the example with (1,2) and (1,5), plotting these two points leads to the vertical line test failing implying we don't have a function.
---------------------------------
---------------------------------
Explanation:
The inputs are x = -3, x = -1, x = 1, x = 5. They are the first coordinate listed of each point. We don't have any x values repeating so this means we have a function. Each input leads to exactly one output which is what choice B is stating. The domain is the set of allowed inputs, or x values. The range is the set of possible y outputs.
If we had something like (1,2) and (1,5) then the input x = 1 leads to more than one output (y = 2 and y = 5). This example means we don't have a function
If you graph the points (-3, -2), (-1,0), (1,0) and (5,-2) as shown in the attached image, then you'll notice that it is impossible to pass a single line through more than one point. Therefore this graph passes the vertical line test visually proving we have a function.
Going back to the example with (1,2) and (1,5), plotting these two points leads to the vertical line test failing implying we don't have a function.