A 95% confidence interval for the proportion of non-fatal accidents involving a distracted driver using some kind of electronic device is 62.5%<x<71.61%
The 95% confidence interval for the proportion is expressed according to the formula;

p is the proportion = 268/400 = 0.67
z is the 95% z-score = 1.96
n is the sample space = 400
Substitute the given parameters into the formula to have:

Hence a 95% confidence interval for the proportion of non-fatal accidents involving a distracted driver using some kind of electronic device is 62.5%<x<71.61%
Learn more on confidence interval here: brainly.com/question/17212516
hi
Two triangles are congruent if their corresponding sides are equal in length, and their corresponding angles are equal in measure.
For this case we have the following inequality:

We multiply both sides of the equation by -1.
By doing this, change the symbol of the inequality.
We have then:

From here, we clear the value of x.
We have then:
Answer:
The solution set is:
{x | x R, x < -12}
Answer:
![\large\boxed{\sqrt[3]{\left(\dfrac{15}{4}\right)^2}}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7B%5Csqrt%5B3%5D%7B%5Cleft%28%5Cdfrac%7B15%7D%7B4%7D%5Cright%29%5E2%7D%7D)
Step-by-step explanation:
![a^\frac{n}{m}=\sqrt[m]{a^n}\\---------------------\\\\\left(5\times\dfrac{3}{4}\right)^\frac{2}{3}=\left(\dfrac{5\times3}{4}\right)^\frac{2}{3}=\left(\dfrac{15}{4}\right)^\frac{2}{3}=\sqrt[3]{\left(\dfrac{15}{4}\right)^2}](https://tex.z-dn.net/?f=a%5E%5Cfrac%7Bn%7D%7Bm%7D%3D%5Csqrt%5Bm%5D%7Ba%5En%7D%5C%5C---------------------%5C%5C%5C%5C%5Cleft%285%5Ctimes%5Cdfrac%7B3%7D%7B4%7D%5Cright%29%5E%5Cfrac%7B2%7D%7B3%7D%3D%5Cleft%28%5Cdfrac%7B5%5Ctimes3%7D%7B4%7D%5Cright%29%5E%5Cfrac%7B2%7D%7B3%7D%3D%5Cleft%28%5Cdfrac%7B15%7D%7B4%7D%5Cright%29%5E%5Cfrac%7B2%7D%7B3%7D%3D%5Csqrt%5B3%5D%7B%5Cleft%28%5Cdfrac%7B15%7D%7B4%7D%5Cright%29%5E2%7D)
Answer:

Step-by-step explanation:
![\left(5^\frac{3}{4}\right)^\frac{2}{3}\\\\\text{Use}\ (a^n)^m=a^{nm}\\\\5^{\frac{3}{4}\cdot\frac{2}{3}}=5^{\frac{1}{2}\cdot\frac{1}{1}}=5^\frac{1}{2}=\sqrt[2]5=\sqrt5](https://tex.z-dn.net/?f=%5Cleft%285%5E%5Cfrac%7B3%7D%7B4%7D%5Cright%29%5E%5Cfrac%7B2%7D%7B3%7D%5C%5C%5C%5C%5Ctext%7BUse%7D%5C%20%28a%5En%29%5Em%3Da%5E%7Bnm%7D%5C%5C%5C%5C5%5E%7B%5Cfrac%7B3%7D%7B4%7D%5Ccdot%5Cfrac%7B2%7D%7B3%7D%7D%3D5%5E%7B%5Cfrac%7B1%7D%7B2%7D%5Ccdot%5Cfrac%7B1%7D%7B1%7D%7D%3D5%5E%5Cfrac%7B1%7D%7B2%7D%3D%5Csqrt%5B2%5D5%3D%5Csqrt5)