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Vedmedyk [2.9K]
3 years ago
6

A math problem asks when two brothers will have saved the same amount of money. When Marta writes and solves the equation, her f

inal step is 3 = 7.
Assuming Marta has done everything correctly, how should she interpret this solution?
Mathematics
1 answer:
Bezzdna [24]3 years ago
3 0
That it wiil not equal out to be the same unless one of them start with money
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Someone that can help me out please
MAXImum [283]

Answer: I got 32

Step-by-step explanation:

I got 32

8 0
3 years ago
The distance by road from town A to town B is 257 km. What is 50% of that distance?
Marina86 [1]

Answer: 128.5km

Step-by-step explanation:

Since we are given the information that the distance by road from town A to town B is 257 km. To get 50% of the distance, we simply have to multiply the distance given by 50%. This will be:

= 50% × 257km

= 50/100 × 257km

= 0.5 × 257km

= 128.5km

Therefore, 50% of the distance is 128.5km.

3 0
2 years ago
Someone help meh and tell me how u did it
morpeh [17]

Answer: 2 4/9

The decimal equivalent is 2.44

Step-by-step explanation:

It may help to convert the fractions to decimals. Divide the numerator by the denominator.

2 3/8 is 2.375

2 1/8 is 2.125 etc.

Remember that absolute value is considered positive. Then put the numbers in order.

7 0
3 years ago
Read 2 more answers
Find maclaurin series
Mumz [18]

Recall the Maclaurin expansion for cos(x), valid for all real x :

\displaystyle \cos(x) = \sum_{n=0}^\infty (-1)^n \frac{x^{2n}}{(2n)!}

Then replacing x with √5 x (I'm assuming you mean √5 times x, and not √(5x)) gives

\displaystyle \cos\left(\sqrt 5\,x\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt5\,x\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^{2n}}{(2n)!}

The first 3 terms of the series are

\cos\left(\sqrt5\,x\right) \approx 1 - \dfrac{5x^2}2 + \dfrac{25x^4}{24}

and the general n-th term is as shown in the series.

In case you did mean cos(√(5x)), we would instead end up with

\displaystyle \cos\left(\sqrt{5x}\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt{5x}\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^n}{(2n)!}

which amounts to replacing the x with √x in the expansion of cos(√5 x) :

\cos\left(\sqrt{5x}\right) \approx 1 - \dfrac{5x}2 + \dfrac{25x^2}{24}

7 0
2 years ago
Please help. Complete the following statement
KIM [24]

Your answer would be f(0)=7.07

1. Substitute 0 into x.

2(0)^2+5√(0+2)

2. Simplify

2(0)+5√2

0+5√2

5√2

7.07

This is the simplest and rounded form, therefore, it is the answer to your question.

5 0
3 years ago
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