A math problem asks when two brothers will have saved the same amount of money. When Marta writes and solves the equation, her f
1 answer:
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Answer:
A non-equilateral rhombus.
Step-by-step explanation:
We can solve this graphically.
We start with square:
ABCD
with:
A = (11, - 7)
B = (9, - 4)
C = (11, - 1)
D = (13, - 4)
Only with the vertices, we can see that ABCD is equilateral, as the length of each side is:
AB = √( (11 - 9)^2 + (-7 -(-4))^2) = √( (2)^2 + (3)^2) = √(4 + 9) = √13
BC = √( (11 - 9)^2 + (-1 -(-4))^2) = √13
CD = √( (11 - 13)^2 + (-1 -(-4))^2) = √13
DA = √( (11 - 13)^2 + (-7 -(-4))^2) = √13
And we change C by C' = (11, 1)
In the image you can see the 5 points and the figure that they make:
The figure ABCD is a rhombus, and ABC'D is also a rhombus, the only difference between the figures is that ABCD is equilateral while ABC'D is not equilateral.
The ratio shown in fraction form would be; 
Now to convert it to its simplest form, you need to find their greatest common factor; (so in this case it would be 28...cause 28 goes into 56 evenly)
*Now divide both terms by 28
28 ÷ 28 = 1
56 ÷ 28 = 2
so your ratio 28 to 56 in simplest form is..
Hope this helps :)
Now to convert it to its simplest form, you need to find their greatest common factor; (so in this case it would be 28...cause 28 goes into 56 evenly)
*Now divide both terms by 28
28 ÷ 28 = 1
56 ÷ 28 = 2
so your ratio 28 to 56 in simplest form is..
Hope this helps :)