In a throw of 2 fair dice, there are 6*6=36 equiprobability outcomes.
To get a sum of 5, there are 4 ways, (1,4),(2,3),(3,2),(4,1) with probability of 4/36=1/9
To get at least one 5, there are 6+6-1=11 outcomes (note (5,5) has been counted in both, so subtracted from sum). The probability is 11/36
Since the two events are mutually exclusive (once we have a five, the sum can no longer be 5), we can add the probabilities to get the probability of one event or the other.
P(sum of 5 OR at least one 5)=1/9+11/36=4/36+11/36=15/36=5/9
Answer:72 are boys.
Step-by-step explanation:
40%of 180 is 72.
Answer:
x
=
−
5.35424868 ,
−
10.64575131
Step-by-step explanation:
Answer:
4x(3x^2-x+5)
Step-by-step explanation:
12x^3-4x^2+20x
=4x(3x^2-x+5)
Multiples of 4: 4,8,12,16,20,24,28,32,36,40,44,48,52,56,60
12 24 36 and 48 are the only common factors
so 4 days
