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forsale [732]
3 years ago
9

On a coordinate plane, a curved line begins at point (negative 2, negative 3), crosses the y-axis at (0, negative .25), and the

x-axis at (1, 0).
What is the domain of the function on the graph?
Mathematics
1 answer:
shepuryov [24]3 years ago
7 0

Answer:

Option D

Step-by-step explanation:

correct answer on edge :)

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Where is most of the mass in the universe found
xeze [42]

Answer:

The milky way galaxy

Step-by-step explanation:

It contains approximately 200 billion stars, and weighing about 1.7 trillion times the mass of the sun

8 0
4 years ago
Determine if the rates are equivalent. Explain your reasoning. 5 cans of soup for $3.75; 8 cans of soup for $6.00
grandymaker [24]

I don't think they are equivalent. try it yourself


3 0
3 years ago
The cost of a large pizza is given by c = 0.50t + 18, where c is the total cost and t is the number of toppings. The cost of a m
Mashutka [201]
The toppings would still cost 0.50 each (since it is just toppings)

The large pizza costs $18 if you do not have any toppings
The medium costs half of the large

18/2 = 9

The medium costs $9 without any toppings, so your new equation will be:

c = 0.50t + 9

hope this helps 
6 0
4 years ago
Read 2 more answers
The theater's income in dollars are sold is(20x18)x5.use properties to find the total income.what property is (20x18)x5. the pro
Pie
Associative Property of Addition
4 0
3 years ago
What is the standard form of the equation of a line for which the length of the normal segment to the origin is 8 and the normal
jeka57 [31]
Slope of line = tan(120) = -tan(60) = - √3
Distance from origin = 8

Let equation be Ax+By+C=0
then -A/B=-√3, or
B=A/√3.
Equation becomes
Ax+(A/√3)y+C=0

Knowing that line is 8 units from origin, apply distance formula
8=abs((Ax+(A/√3)y+C)/sqrt(A^2+(A/√3)^2))
Substitute coordinates of origin (x,y)=(0,0)  =>
8=abs(C/sqrt(A^2+A^2/3))
Let A=1 (or any other arbitrary finite value)
solve for positive solution of C
8=C/√(4/3) => C=8*2/√3 = (16/3)√3

Therefore one solution is
x+(1/√3)+(16/3)√3=0
or equivalently
√3 x + y + 16 = 0

Check:
slope = -1/√3  .....ok
distance from origin
= (√3 * 0 + 0 + 16)/(sqrt(√3)^2+1^2)
=16/2
=8  ok.

Similarly C=-16 will satisfy the given conditions.

Answer  The required equations are
√3 x + y = ± 16 
in standard form.

You can conveniently convert to point-slope form if you wish.




4 0
4 years ago
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