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3 years ago

9

On a coordinate plane, a curved line begins at point (negative 2, negative 3), crosses the y-axis at (0, negative .25), and the

x-axis at (1, 0).
What is the domain of the function on the graph?

1 answer:

shepuryov [24]3 years ago

7 0

Answer:

Option D

Step-by-step explanation:

correct answer on edge :)

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2. In the circle shown, secants PE and PF have been drawn such that mCE  82 , mDF  98 and the ratio 3. In circle O, tangent

Andrew [12]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The arc PR is $\theta _{PR} = 84$

Step-by-step explanation:

A descriptive diagram of the diagram given in the question is shown on the first uploaded image

In the circle tangent $\= {M \= Q}$ , secant $PE$ and chord $PF$ are drawn

given that $\theta _ {MPQ} = 102^o$ , $\theta _{M} = 60^o$

The objective is to determine PR

From the diagram we see that MQ is a straight which implies that the the angle

$\theta_{NPM} = 180 -102$

$\theta_{NPM} = 78^o$

Now looking at triangle NMP we see that

$\theta _{MNP} = 180 -[ \theta_{NMP} + \theta _{NPM}]$

$\theta _{MNP} = 180 - [60 + 78 ]$

$\theta _{MNP} = 42 ^o$

Now the measure of an inscribed angle is half the measure of its arc intercepted, this statement is the inscribed angle theorem

So with the knowledge

Then

$\theta_{RNP} = \frac{1}{2} \theta_{PR}$

Looking at the diagram we see that

$\theta _{MNP} = \theta_{RNP} = 42 ^o$

$42 = \frac{1}{2} \theta _{PR}$

$\theta _{PR} = 2 * 42$

$\theta _{PR} = 84$

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3 years ago