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nekit [7.7K]
3 years ago
7

You are conducting a study on the health of people who have been exposed to radiation and those who have not been exposed to rad

iation. Which of these methods of obtaining data should you most likely adopt and why?
a. an observational study because it involves the pre-existing condition of the subjects
b. an experimental study because it will give the most accurate results
c. an experimental study because results can be obtained much faster using this technique
d. a sample survey with only people who were not exposed to radiation because it involves random selection
e. a sample survey with only people who were exposed to radiation because it involves random selection
Mathematics
2 answers:
coldgirl [10]3 years ago
8 0

Answer:

a. an observational study because it involves the pre-existing condition of the subjects

Step-by-step explanation:

Given that You are conducting a study on the health of people who have been exposed to radiation and those who have not been exposed to radiation.

Already some people exposed to radiation and not exposed is being taken for sample.

Hence here no change is made so it is only an observational study and not experimental study.

Option e, d are incorrect sinc both groups must be observed.

Option b and c are incorrect because this is not an experimental study.

Hence correct option is

a. an observational study because it involves the pre-existing condition of the subjects

nadya68 [22]3 years ago
5 0
Thank you for posting your question here at brainly. Feel free to ask more questions.   
<span>
The best and most correct answer among the choices provided by the question is </span><span>a. an observational study because it involves the pre-existing condition of the subjects</span>.    
      <span>
Hope my answer would be a great help for you.  </span>
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Answer and Step-by-step explanation: Area of a right triangle, (as any other triangle), is calculated as:  A1=\frac{(base)(height)}{2}

Area of a rectangle is calculated as: A2=(side)(side)

Area of a right trapezoid is: A3=\frac{(a+b)h}{2}, where:

a is short base

b is long base

h is height

1) Expressing areas in terms of x:

Area of triangle S1:

S1=\frac{(2x-3)(4x-6)}{2}

S1=4x^{2}-12x+9

Area of rectangle S2:

S2 = (4x-6)(3x-2)

S2=12x^{2}-26x+12

Area of trapezoid S3:

S3=\frac{(2x+3+4x+1)(2x-3)}{2}

S3=\frac{(6x+4)(2x-3)}{2}

S3=6x^{2}-5x-6

2) a) S=4x^{2}-12x+9+12x^{2}-26x+12-(6x^{2}-5x-6)

S=4x^{2}-12x+9+12x^{2}-26x+12-6x^{2}+5x+6

S=10x^{2}-33x+37

Which is the same as S = (2x-3)(5x-9)

b) For the areas to be the same:

\frac{(3x-2+3x-2+2x-3)(4x-6)}{2}=\frac{(6x+4)(2x-3)}{2}

\frac{(8x-7)(4x-6)}{2}=\frac{(6x+4)(2x-3)}{2}

32x^{2}-48x-28x+42=12x^{2}+8x-18x-12

20x^{2}-66x+54=0

Using Bhaskara to solve the second degree equation:

\frac{66+\sqrt{(-66)^{2}-(4.20.54)} }{2(20)}

x_{1}=\frac{66+6}{40} = 1.8

x_{2}=\frac{66-6}{40} = 1.5

For the areas of AFGC and ADEB to be equal, x has to be 1.5 or 1.8.

c) <u>Expand</u> <u>a</u> <u>polynomial</u> (or equation) is to multiply all the terms, remiving the parenthesis. <u>Reduce</u> <u>a</u> <u>polynomial</u> (or equation) is to combine terms alike,e.g.:

S=(2x-3)(5x-9)

S=10x^{2}-18x-15x+27 (expand)

S=10x^{2}-33x+27 (reduce)

d) For area of AFCG to be bigger than area of ADEB by 27:

32x^{2}-48x-28x+42=12x^{2}+8x-18x-12+27

32x^{2}-48x-28x+42=12x^{2}+8x-18x+15

20x^{2}-66x+27=0

Solving:

\frac{66+\sqrt{(-66)^{2}-(4.20.27)} }{2(20)}

\frac{66+46.86}{40}

x_{1}=\frac{66+46.86}{40}= 2.82

x_{2}=\frac{66-46.86}{40} = 0.48

According to the enunciation, x cannot be less than 1.5, then, the value of x so that area AFGC exceeds the area ADEB by 27 is 2.82

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