2 years ago

Need some geometry help

1 answer:

6 0

Check the picture below.

that means

angle AFB is 27 + 2 = 29

angle BFC is 2(27) + 12 = 66

and angle CFD is 2(27) or 54

so hmmmm, you'd know which one isn't there.

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Which of the following give an equation of a line that passes through the point (6/5,-19,5) and is parallel to the line that pas

Ilya [14]

Parallel lines, have the same slope, so the slope of the line through 0,0 and -2,-12, is the same as for the line running through (6/5,-19.5) as well, so what is it anyway?

$\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ 0}}\quad ,&{{ 0}})\quad 
% (c,d)
&({{ -2}}\quad ,&{{ -12}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{-12-0}{-2-0}\implies \cfrac{-12}{-2}\implies 6$

so, we're looking for the equation of a line whose slope is 6, and goes through (6/5,-19/5)

$\bf \begin{array}{lllll}
&x_1&y_1\\
% (a,b)
&({{ \frac{6}{5}}}\quad ,&{{ -\frac{19}{5}}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 6
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-\left( -\frac{19}{5} \right)=6\left(x-\frac{6}{5} \right)
\\\\\\
y+\cfrac{19}{5}=6x-\cfrac{36}{5}\implies y=6x-\cfrac{36}{5}-\cfrac{19}{5}\implies y=6x-\cfrac{55}{5}
\\\\\\
y=6x-11$

6 0

3 years ago

Harris is building a deck around his pool. His contractor charges $525 for labor plus an additional $4.75 per square foot for ma

xenn [34]

Answer:

Step-by-step explanation:525 is the constant so no variable should be next to it

6 0

2 years ago

Read 2 more answers

What is 93•10•10•10•10•10•10•10

Vsevolod [243]

930,000,000 would be your answer