Need some geometry help

Mathematics

1 answer:

GenaCL600 [577]3 years ago

6 0

Check the picture below.

that means

angle AFB is 27 + 2 = 29

angle BFC is 2(27) + 12 = 66

and angle CFD is 2(27) or 54

so hmmmm, you'd know which one isn't there.

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What is the equation of the line that passes through points (2, −6) and (−4, 3)?

maria [59]

Answer:

y = -3/2x - 3

Step-by-step explanation:

Slope-Intercept Form: y = mx + b

Slope Formula: $m=\frac{y_2-y_1}{x_2-x_1}$

Step 1: Find slope m

$m=\frac{3-(-6)}{-4-2}$

$m=\frac{3+6}{-6}$

$m=\frac{9}{-6}$

$m=\frac{-3}{2}$

y = -3/2x + b

Step 2: Find y-intercept b

3 = -3/2(-4) + b

3 = 6 + b

b = -3

Step 3: Rewrite linear equation

y = -3/2x - 3

4 0

4 years ago

Read 2 more answers

El Generico public high school got a new flagpole. But they completely forgot to buy a cord and NO ONE knows how tall the flagpo

Pie

In measurement problems such as these, we can use proportional relationships to determine the length or measure of triangular sides.This works because the two figures are similar. Our proportion is going to have a variable since we do not know the height of one of the flagpoles. It will be set up as such:

$\frac{5}{8}$ = $\frac{x}{32}$

We cross multiply, then divide to solve this proportion.

32 x 5 = 160.

160/8 = 20.

This means the height of the flagpole is 20 feet high. To fit the height of the flag pole, the cord the school should buy for the flagpole should be 20 feet long.

5 0

4 years ago

If f(x)= 4x+3 and g(x)= 3x evalute f(x). g(x) for x=-1 over 2

padilas [110]

$\bf \begin{cases}
f(x)=4x+3\\
g(x)=3x\\
------------\\
f(x)\cdot g(x)=(4x+3)(3x)\\
\qquad \qquad \qquad 12x^2+9x
\end{cases}
\\\\\\
\boxed{x=-\cfrac{1}{2}}\qquad \qquad 12\left( -\frac{1}{2} \right)^2+9\left( -\frac{1}{2} \right)\implies 12\left( -\frac{1}{2} \right)\left( -\frac{1}{2} \right)+9\left( -\frac{1}{2} \right)
\\\\\\
12\left( \cfrac{1}{4} \right)-\cfrac{9}{2}\implies 3-\cfrac{9}{2}\implies \cfrac{6-9}{2}\implies \cfrac{-3}{2}\implies -1\frac{1}{2}$