Jessica is selling books during the summer to earn money for college. She
1 answer:
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Answer:
none of the above
Step-by-step explanation:
You can try the points in the equations (none works in any equation), or you can plot the points and lines (see attached). <em>You will not find any of the offered answer choices goes through the given points</em>.
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You can start with the 2-point form of the equation of a line. For points (x1, y1) and (x2, y2) that equation is ...
y = (y2 -y1)/(x2 -x1)·(x -x1) +y1
Filling in the given points, we get ...
y = (3 -1)/(2 -4)·(x -4) +1
y = 2/(-2)(x -4) +1 . . . . . simplify a bit
y = -x +4 +1 . . . . . . . . . simplify more
y = -x +5 . . . . . . . . . . . slope-intercept form
Step-by-step explanation:
by using y=uv derivative formula and stationary mean y' = 0
y' = 3(x–2)⁴ + 3(3x–1)(x–2)³ = 0
cancel 3 and factorize
(x–2+3x–1)(x–2)³ = 0
x = ¾ or x = 2
we got point and (2,0)
Notice the picture below
so.... the angle of depression, is above in dashed lines.... however, the angle of depression, is identical to the angle of elevation from the water, since, both angles are "alternate interior" angles
now, using the 45-45-90 rule, then we know the swimmer is 90 feet from the lighthouse, then just use the tangent ratio to get "x"
so.... the angle of depression, is above in dashed lines.... however, the angle of depression, is identical to the angle of elevation from the water, since, both angles are "alternate interior" angles
now, using the 45-45-90 rule, then we know the swimmer is 90 feet from the lighthouse, then just use the tangent ratio to get "x"