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Maru [420]
3 years ago
6

Write in simplest form. Check by multiplying. 2/7÷2=

Mathematics
1 answer:
satela [25.4K]3 years ago
6 0
2/7 x 1/2 = 2/14
1/7

1/7 is the answer !!!! :) your welcome
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PLEASE HELP ME!!!!!!!!
alexandr1967 [171]

Answer:

well...

Step-by-step explanation:

Im to lazy to try and figure it out sorry

3 0
3 years ago
NEED HELP ASAP i need to simplify (f+g)(x) if f(x) = x+4 and g(x) = 3x^2-8
kogti [31]

We can also think of this problem as f(x) + g(x). Therefore, all we need to do is add the two functions together.

x + 4 + 3x^2 - 8 || Write it out!

3x^2 + x + 4 - 8 || Rearrange in order of decreasing exponents. No need to combine and rearrange all at once!

3x^2 + x - 4 || Combine like terms!

Hope this helps!! :)

5 0
3 years ago
HELP PRECALC I DO NOT UNDERSTAND AT ALLLLL!!!!!!!!!!!!!!!!!!!!!!
Arlecino [84]

Answer:

  φ ≈ 1.19029 radians   (≈ 68.2°)

Step-by-step explanation:

There are simple formulas for A and φ in this conversion, but it can be instructive to see how they are derived.

We want to compare ...

  y(t) = Asin(ωt +φ)

to

  y(t) = Psin(ωt) +Qcos(ωt)

Using trig identities to expand the first equation, we have ...

  y(t) = Asin(ωt)cos(φ) +Acos(ωt)sin(φ)

Matching coefficients with the second equation, we have ...

  P = Acos(φ)

  Q = Asin(φ)

The ratio of these eliminates A and gives a relation for φ:

  Q/P = sin(φ)/cos(φ)

  Q/P = tan(φ)

  φ = arctan(Q/P) . . . . taking quadrant into account

__

We can also use our equations for P and Q to find A:

  P² +Q² = (Acos(φ))² +(Asin(φ))² = A²(cos(φ)² +sin(φ)²) = A²

  A = √(P² +Q²)

_____

Here, we want φ.

  φ = arctan(Q/P) = arctan(5/2)

  φ ≈ 1.19029 . . . radians

8 0
4 years ago
Please help me please
bulgar [2K]
1) p-2
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3 years ago
I don't know how to plug in 1,5,10 for a function
castortr0y [4]

explanation:

in regular math: if the function is written as function notation, replace all x's in the expression with your number and solve.

in brainly: click the math button, {it looks like a square root sign with an x inside} press whichever function or process you like and in the text box it should say something like " /[operation]{x}{y} "

in those curly brackets around x and y is where your numbers should go. just get rid of the variable and put it in your number to make the function/process they way you want it to go instead of having those placeholder variables.

4 0
4 years ago
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