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2 years ago

E.C. What is the standard equation of a circle with center (h,k) and radius r in the coordinate plane?

Mathematics

2 answers:

vitfil [10]2 years ago

8 0

Answer:

(x − 4)2 + (y + 6)2 = 25

(x − 4)2 + (y − (-6))2 = 52

When I compare my equation with the standard form, (x − h)2 + (y − k)2 = r2, I get h = 4, k = -6, and r = 5. The center is at (4, -6), and the length of the radius is 5.

Step-by-step explanation:

edmentum

LuckyWell [14K]2 years ago

4 0

Answer:

(x-h)^2 + (y-k)^2 = r^2

Step-by-step explanation:

Here, we want to write the standard equation of the circle

We have this as;

(x-h)^2 + (y-k)^2 = r^2

The above equation is the standard equation for the circle

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What is the volume of this sphere?

JulsSmile [24]

<h3>Answer: 24416.64</h3>

Work Shown:

$V = (4/3)*\pi*r^3\\\\V \approx (4/3)*3.14*18^3\\\\V \approx 24416.64\\\\$

6 0

1 year ago

A circle has center at –6 + 2i and a point on the circle at 4 + 26i. Which of the following points is also on the circle?

Alenkasestr [34]

Answer:
–16 – 22i
Step-by-step explanation:
The radius of the circle = 4 + 26i - (-6 + 2i)
= 10 + 24i.
The radius will be the absolute values of this |10 + 24i|.

If a point is on the circle then it's distance from the centre must be 10+ 24i.
-19 + 15i - (-6 + 2i) = -13 - 13i , so this is not on the circle.
-16 - 22i - (-6 + 2i) = -10 - 24i = |10 + 24i| , so this is on the circle.
5 + 16i - (-6 + 2i) = 11 + 14i , so this is not on the circle.
20 - 24i - (-6 + 2i) = 26 - 26i. so this is not on the circle.

3 0

1 year ago

Find the height of the building below by using your knowledge of trigonometry.

Lilit [14]

Answer:

50 $\sqrt{3}$

Step-by-step explanation:

The figure represents a 30-60-90 special triangle

in this special right triangle the measure of sides lengths is represented by

a, a $\sqrt{3}$ , and 2a

The side length that sees angle measure 30 is represented by a and here we see a = 50m

The height of the building, which sees angle measure 60, is equal to

50 $\sqrt{3}$

5 0

2 years ago

How do I find the values of these

skad [1K]

Since the triangles are similar, then 32 = x+7 those two angles are too
solve for "x"

now using proportions $\bf \cfrac{\textit{small triangle}}{\textit{large triangle}}\qquad \cfrac{JK}{18}=\cfrac{12}{12+10}$

solve for JK

$\bf \cfrac{\textit{small triangle}}{\textit{large triangle}}\qquad \cfrac{12}{12+10}=\cfrac{9}{9+KG}\implies 12(9+KG)=(22)9
\\\\\\
108+9KG=198$

solve for KG

the scale factor of the perimeter of both triangles is just the same as the ratio of the sides, or $\bf \cfrac{12}{12+10}$

3 0

2 years ago

Vince weighs 160 pounds, and his friend Nadir weighs 140 pounds. Nadir calculated that his weight on another planet would be abo

Ymorist [56]

Answer: 64 lbs

Step-by-step explanation:

I divided 56/140 and got 0.4. Then multiplied 0.4 by 160 and got 64. SOunds about right to me.

You can double check by multipling 0.4 by 140 and you get 56.

4 0

2 years ago

Read 2 more answers