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RUDIKE [14]
2 years ago
8

E.C. What is the standard equation of a circle with center (h,k) and radius r in the coordinate plane?

Mathematics
2 answers:
vitfil [10]2 years ago
8 0

Answer:

(x − 4)2 + (y + 6)2 = 25

(x − 4)2 + (y − (-6))2 = 52

When I compare my equation with the standard form, (x − h)2 + (y − k)2 = r2, I get h = 4, k = -6, and r = 5. The center is at (4, -6), and the length of the radius is 5.

Step-by-step explanation:

edmentum

LuckyWell [14K]2 years ago
4 0

Answer:

(x-h)^2 + (y-k)^2 = r^2

Step-by-step explanation:

Here, we want to write the standard equation of the circle

We have this as;

(x-h)^2 + (y-k)^2 = r^2

The above equation is the standard equation for the circle

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Answer:

uld you like to ask?

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Pair of Linear Equations in Two Variables

Algebraic Solution of a Pair of Linear Equations

Solve: 3x + 4y = 10,2x - 2y...

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Asked on December 27, 2019 byShweta Rudravaram

Solve: 3x+4y=10,2x−2y=2 by the method of elimination.

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ANSWER

3x+4y=10 …………..(1)

2x−2y=2 (or) x−y=1 …………(2)

(1) ⇒(3x+4y=10)1

(2) ⇒(x−y=1)3

                     _____________________

                                3x+4y=10

                                3x−3y=3

                      _____________________

                                    7y=7

∴y=1

Put y=1 in (1) we get 3x+4×1=10

3x=10−4=6

∴x=36=2

Hence x=2,y=1.

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3 years ago
Jack knows the surface area of a cylinder and its radius. He wants to find the cylinder's height. He needs to rewrite the formul
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2 years ago
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Consider the curve y=x2+3x+5. (a) Find the slope of the secant line to the curve through the points P=(4,33) and Q=(4+h,(4+h)2+3
lawyer [7]

Answer:

a) The slope of the secant line is 11 + h

b) The slope of the curve at P is 11

c) The equation of the tangent line at P is y = 11x - 11

Step-by-step explanation:

y=x²+3x+5

(a) Find the slope of the secant line to the curve through the points P=(4,33) and Q=(4+h,(4+h)²+3(4+h)+5)

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(b) Use your answer from part (a) to find the slope of the curve at the point P.

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The slope of the curve at P is 11

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The equation of the tangent line at P is y = 11x - 11

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