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erik [133]
2 years ago
12

Add the fractions and simplify the answer 1/2 +2 /3

Mathematics
2 answers:
Brilliant_brown [7]2 years ago
5 0
So first convert the denoenator (bottom n umber) to the sam enumber


1/2 and 2/3
the numbers are 2 and 3
find least comon multiple
easy way to convert is multiply each by bottom number of the other over the other exg
1/2 +2/3
1/2 times 3/3+2/3 times 2/2
3/6+4/6
(7)/6
7/6
1 and 1/6
IrinaVladis [17]2 years ago
4 0
What we are going to do is add \frac{1}{2} by \frac{2}{3}. The first thing we do is make common denominators for \frac{1}{2} and \frac{2}{3}:\frac{1*3}{2*3}= \frac{3}{6} \ and \  \frac{2*2}{3*2}= \frac{4}{6}. Now we add \frac{3}{6} by \frac{4}{6}: \frac{3}{6}+ \frac{4}{6}= \frac{7}{6}. Now we make \frac{7}{6} a mixed number:\frac{7}{6}=1 \frac{1}{6}. Therefore, your answer is \boxed{\boxed{1 \frac{1}{6}}}. Hoped I helped. :)
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3 years ago
Solve using long division <br> Please
madreJ [45]

1. Solution,\frac{2x^3+4x^2-5}{x+3}:\quad 2x^2-2x+6-\frac{23}{x+3}

Steps:

\mathrm{Divide}\:\frac{2x^3+4x^2-5}{x+3}:\quad \frac{2x^3+4x^2-5}{x+3}=2x^2+\frac{-2x^2-5}{x+3}

\mathrm{Divide}\:\frac{-2x^2-5}{x+3}:\quad \frac{-2x^2-5}{x+3}=-2x+\frac{6x-5}{x+3}

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\mathrm{Simplify}, =2x^2-2x+6-\frac{23}{x+3}

\mathrm{The\:Correct\:Answer\:is\:2x^2-2x+6-\frac{23}{x+3}}

2. Solution, \frac{4x^3-2x^2-3}{2x^2-1}:\quad 2x-1+\frac{2x-4}{2x^2-1}

Steps:

\mathrm{Divide}\:\frac{4x^3-2x^2-3}{2x^2-1}:\quad \frac{4x^3-2x^2-3}{2x^2-1}=2x+\frac{-2x^2+2x-3}{2x^2-1}

\mathrm{Divide}\:\frac{-2x^2+2x-3}{2x^2-1}:\quad \frac{-2x^2+2x-3}{2x^2-1}=-1+\frac{2x-4}{2x^2-1}

\mathrm{The\:Correct\:Answer\:is\:2x-1+\frac{2x-4}{2x^2-1}}

\mathrm{Hope\:This\:Helps!!!}

\mathrm{-Austint1414}

4 0
3 years ago
Please help in maths
Readme [11.4K]

The equivalent expressions of 22c + 33d are (a), (c) and (e)

<h3>How to determine the equivalent expressions?</h3>

The expression is given as:

22c + 33d

Factor out 11 from the expression

11(2c + 3d)

Multiply by 1

1 * 11(2c + 3d)

Express 1 as -1 * -1

-1 * -1 * 11(2c + 3d)

Evaluate the product

(-11) * (-2c - 3d)

Also, we have:

22c + 33d

Multiply by 1

(22c + 33d) * 1

Express 1 as 3/3

(22c + 33d) * 3/3

Evaluate the product

(66c + 99d) * 1/3

Hence, the equivalent expressions are (a), (c) and (e)

Read more about equivalent expressions at:

brainly.com/question/27911936

#SPJ1

7 0
1 year ago
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