Answer:
a15 = 50
t25 = 33554427
Step-by-step explanation:
<em>Insert/Substitute the number given in for n.</em>
a15 = 3(15) + 5
a15 = 45 + 5
a15 = 50
~
t25 = 2^25 - 5 <em>2 times itself 25 times. 25 is the exponent in this equation</em>
t25 = 33554432 - 5
t25 = 33554427
Answer:
infinitely many solutions
Step-by-step explanation:
Answer:
-9
Step-by-step explanation:
-7x+12=75
-12 -12
-7x= 63
divide by -7 on both sides
x = -9
X² + 11x - 26 = 0
x² - 25 = 0
(x + 13)(x - 2) = 0
(x + 5)(x - 5) = 0
x = -13
x = 2
x = -5
x = 5
Answer:
B) To represent the distance between 3 and −5 on a number line, the correct expression is I(3) - (-5)I .
Step-by-step explanation:
Here the point A is given as 3 on number line.
Point B is given as -5 on number line.
To find : IA-BI
The distance between any two point A and B is given as IA-BI.
Now, to find the absolute value:
IA-BI = I (3) - (-5)I
or, IA-BI = I (3) + 5I = I8I
= 8 units
or, IA-BI = 8 units
Hence, on the number line, the distance between -5 and 3 is 8 units.
And, to represent the distance between 3 and −5 on a number line, the correct expression is I(3) - (-5)I .
