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Anestetic [448]
3 years ago
6

Area. Please help. I don’t understand the question.

Mathematics
2 answers:
photoshop1234 [79]3 years ago
8 0

Answer:

Step-by-step explanation:

aleksandr82 [10.1K]3 years ago
5 0

Answer:

look at the picture i sent

Step-by-step explanation:

do not forget to round the answer

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A calculator is required to obtain the final answer on this question. A solid metal sphere at room temperature 20oC is dropped i
yKpoI14uk [10]

Answer:

T = 47.1875°C

Step-by-step explanation:

Given:

Surrounding temp, Ts = 100°C

Initial Temperature ,T0= 20°C

Increase in temperature = 15°C

Final temperature, T = 20 + 15 = 35°C

Time, t = 9 seconds

Let's take Newton's law of cooling:

T - Ts = (T_0 - Ts)e^k^t

We'll solve for k

35 - 100 = (20 - 100)e^9^k

-65 = (-80)e^9^k

Divide both sides by -5

13 = (16)e^9^k

9k = ln (\frac{13}{16})

k = \frac{1}{9} ln (\frac{13}{16})

k = -0.02307104053

Let's now find the temperature of the ball after 18 seconds in boiling water.

Use the Newton's equation again:

T - Ts = (T_0 - Ts)e^k^t

T - 100 = (20 - 100)e^-0.0^2^3^0^7^1^0^4^0^5^3^*^1^8

T - 100 = (-80)e^-0.0^2^3^0^7^1^0^4^0^5^3^*^1^8

T - 100= -52.8125

T = 100 - 52.8125

T = 47.1875°C

Temperature of the ball after 18 seconds in boiling water is 47.1875°C

5 0
3 years ago
20 POINTS HELP FAST
victus00 [196]

Answer:

brainly.com/question/16576809

Step-by-step explanation:

3 0
3 years ago
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