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3 years ago

Surface area of the below shape

Mathematics

1 answer:

pantera1 [17]3 years ago

6 0

Solve all of the equations below and add all of the solutions to those equations to get your answer.

10x4x2=

8x4x2=

10x8=

(10x8)-(7x6)=

7x2x2=

6x2x2=

7x6=

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A square field with an area of 2000 square ft is to be enclosed by a fence. The slabs are 5ft long.

AysviL [449]

You should divide 2000 by 5.

6 0

3 years ago

3/4 + (1/3 ÷ 1/6) - (-1/2) =?

stepladder [879]

Answer:

[See Below]

Step-by-step explanation:

✦ Turn fractions into decimals:

$\frac{3}{4} =0.75$

$-\frac{1}{2} =-0.5$

(We will do something different for $\frac{1}{3}$ and $\frac{1}{6}$ .)

✦ Divide:

$\frac{1}{3}$ ÷ $\frac{1}{6}=2$

(Since the denominators are multiplies of each other we can divide them without having to change them into decimals.)

✦ Simplified Equation:

$0.75+2-(-0.5)$

✦ Add:

$0.75+2=2.75$

✦ Subtract:

$2.75-(-0.5)=3.25$

(Subtraction rule is if there is 2 negatives next to each other in a problem it turns into a positive.)

✦ So your answer would be:

$\frac{13}{4}$ (Exact Form)

$3~ \frac{1}{4}$ (Mixed Number Form)

$3.25$ (Decimal Form)

~<em>Hope this helps Mate. If you need anything feel free to message me. </em>

8 0

3 years ago

Sam scored 98,25,105,62 and 65 run in 5 matches what was the average score per match

Jet001 [13]

To get the average you need to add all the numbers together and divide by the match number. So, 98+25+105+62+65=355. 355/5=71, therefore the average is 71

7 0

3 years ago

Ms. Pacheco, Mr. Edwards, and Mr. Richards are three math teachers at Turner Middle School. Ms. Pacheco is three years older tha

mina [271]

Ms. Pacheco = P
Mr. Richards = R
Mr. Edwards = E
P = R + 3
E = 2R
R + E = 81
81 = R + 2R
81 = 3R
81 ÷ 3 = R
R = 27
P = R + 3
P = 27 + 3
P = 30
E = 2R
E = 2×27
E = 54

7 0

3 years ago

One hundred items are simultaneously put on a life test. Suppose the lifetimes

romanna [79]

Answer:

a) $\mathrm{E}[\mathrm{T}]=\sum_{\mathrm{H}}^{5} \frac{200}{101-i}$

b) $\mathrm{Var}[\mathrm{T}]=\sum_{k=1}^{5} \frac{(200)^{2}}{(101-i)^{2}}$

Step-by-step explanation:

Given:

The lifetimes of the individual items are independent exponential random variables.

Mean = 200 hours.

Assume, Ti be the time between ( $i-1$ )st and the $ith$ failures. Then, the $T_{i}$ are independent with $\mathrm{T}_{\mathrm{i}}$ being exponential with rate $\frac{(101-i)}{200} .$