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WARRIOR [948]
3 years ago
7

-2\sqrt{3}" alt="3\sqrt{3}+5\sqrt{3}-2\sqrt{3}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Nimfa-mama [501]3 years ago
8 0
If this is for simplify the expression the answers is...
6√3
In decimal form is...
10.39230484...
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A rancher owns a rectangular piece of land that is 4.1 mi long and 2.5 mi wide. Find the units for the perimeter of the rectangl
Naddik [55]

Answer:

13.1mi

Step-by-step explanation:

Length(l) = 4.1mi

Breadth(b) = 2.5 mi

Perimeter of a rectangle = addition of all sides that is = l + l + b + b as a rectangle has 2 opposite equal length and also breadth.

Therefore perimeter = 4.1 + 4.1 + 2.5 + 2.5

= 8.1 + 5

=13.1 mi

I hope this was helpful, Please mark as brainliest

8 0
3 years ago
Read 2 more answers
A line passes through the points......​
Kobotan [32]
Should be the first one
8 0
2 years ago
Read 2 more answers
Rewrite the following polynomial in standard form <br> -x2 + 1 + 2x
fenix001 [56]

Answer:

-5x^4+8x^3-2x+1

Step-by-step explanation:

5 0
2 years ago
In a manufacturing process a random sample of 9 bolts manufactured has a mean length of 3 inches with a standard deviation of .3
Serggg [28]

Answer:

The correct option is (C) (2.769, 3.231).

Step-by-step explanation:

The confidence interval for mean when the standard deviation is not known is:

CI=\bar x\pm t_{\alpha/2, (n-1)}\frac{s}{\sqrt{n}}

Given:

\bar x = 3\\s=0.3\\n=9\\\alpha =1-0.95=0.05

Compute the critical value as follows:

t_{\alpha/2, (n-1)}=t_{0.05/2, (9-1)}=t_{0.025, 8}=2.31

**Use a <em>t</em>-table.

The 95% confidence interval for true mean length of the bolt is:

CI=\bar x\pm t_{\alpha/2, (n-1)}\frac{s}{\sqrt{n}}\\=3\pm 2.31\times \frac{0.30}{\sqrt{9}}\\ =3\pm 0.231\\=(2.769, 3.231)

Thus, the 95% confidence interval for true mean length of the bolt is (2.769, 3.231).

The correct option is (C).

7 0
3 years ago
6x+4y=2 10x-8y=32 what is the exact solution by using elimination
Alexeev081 [22]
First, let's multiply the first equation by two. This is because we have to eliminate either x or y by subtraction or addition so that means either both of the x's or both of the y's in the two equations have to be equal. Thus multiplying the first equation by 2 will give 12x+8y=4.
Next, subtract equation two from equation one:
We get a third equation, 2x-0= -28
Thus, x=-28/2. x= -14
In the same way, to find y, we need to eliminate the x's in both equations. This can be done by multiplying the first equation by 5 and the second by 3
Thus : 30x+20y=10 and 30x-24y=96
Subtracting the second equation from the first, we have 0+44y=-86
y=-86/44
y = 1.96 or 43/22
6 0
3 years ago
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