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IceJOKER [234]
3 years ago
13

on an air Indian flight there are 9 boys 5 indian children, 9 men, 7 foreign boys 14 indians, 6 indian male and 7 foreign female

. What is the number of people on board the plane.​
Mathematics
1 answer:
ololo11 [35]3 years ago
8 0

Answer:

Is it 57?

Step-by-step explanation:

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WHAT IS THE GOAL FOR THE TOPIC OF FINDING THE CENTER AND THE RADIUS OF A CIRCLE GIVEN THE EQUATION?​
yan [13]

The goal is to find the radius of a circle which also helps to get the diameter. Finding the center helps to measure and know the circumference.

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Can someone please answer. There is only one problem. There is a picture. Thank you!
KATRIN_1 [288]
5Red + 6Blue + 4 Black

Total = 5 + 6 = 4 = 15

Probality of Blue, Blue.

P(Blue) = 6/15 = 2/5

P(Blue, Blue) = (2/5)*(2/5) = 4/25
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3. Determine which of the following variables are qualitative and which are quantitative variables. Explain your
Tanya [424]

Answer:

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4 0
1 year ago
What ia the angle of AOC and DOE
natulia [17]

(i) Angle AOC would equal 48°, as it is vertically opposite to angle DOB and they are therefore equal.


(ii) Angle DOE would equal 42°. We can see this because angles on a straight line add up to 180°, and 90 + 48 = 138, so we can do 180 - 138 = 42°.


I hope this helps!

4 0
3 years ago
Newborn males have weights with a mean of 3272.8 g and a standard deviation of 660.2 g. Newborn females have weights with a mean
Maksim231197 [3]

The correct option is:   a female who weighs 1500 g

<em><u>Explanation</u></em>

<u>Formula for finding the z-score</u> is:  z= \frac{X-\mu}{\sigma}

Newborn males have weights with a mean(\mu) of 3272.8 g and a standard deviation(\sigma) of 660.2 g.

So, the z-score for the newborn male who weighs 1500 g will be.......

z(X=1500)=\frac{1500-3272.8}{660.2}=-2.685... \approx -2.69

According to the normal distribution table,  P(z=-2.69)=0.0036 = 0.36\%

Now, newborn females have weights with a mean(\mu) of 3037.1 g and a standard deviation(\sigma) of 706.3 g.


So, the z-score for the newborn female who weighs 1500 g will be.......

z(X=1500)=\frac{1500-3037.1}{706.3}=-2.176... \approx -2.18

According to the normal distribution table,  P(z=-2.18)=0.0146 = 1.46\%

As we can see that the <u>probability that a newborn female has weight of 1500 g is greater than newborn male</u>,  so a newborn female has the weight of 1500 g that is more extreme relative to the group from which he came.

5 0
3 years ago
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