What is the slope and the y-intercept of the following linear equation?
1 answer:
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Your question is incomplete, here is the complete question;
A football is kicked into the air and follows the path defined by h=-2x^2+16x, where x is the time in seconds and h is the height in meters. What is the maximum height reached by the football?
Answer:
maximum height=h=32 meters
Step-by-step explanation:
The given equation is the equation of the parabola or quadratic equation.
The maximum height of the ball will occur at the axis of symmetry.
For the axis of symmetry let h=0,
so,
comparing this equation to standard quadratic/parabola's equation, we get
a= -2, b=16 and c=0
Formula for axis of symmetry is x=-b/2a
x=-16/2*(-2)
x=-16/-4
x=4 it means axis of symmetry is vertical line through the point x=+4, so the maximum height will occur at x=+4
put x=4 to get maximum height as;
Maximum height
Answer:
The range for Problem 18 is
The range for problem 19 is
Step-by-step explanation:
To find the range you subtract the smallest value from the largest value. In problem 18 the largest value was 17.6 and the smallest was 1.5.
In problem 19 the largest value was 181 and the smallest was 14