4. What is the area of a square with side lengths of 3/5 units?

Mathematics

1 answer:

irga5000 [103]3 years ago

4 0

Answer:

9/5 units²

Step-by-step explanation:

Area of a square=s²

A=(3/5)²

A=9/25

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Equation of the line (-6,5) and (8,14) in standard form

blsea [12.9K]

Answer:

$\huge\boxed{9x-14y=-70}$

Step-by-step explanation:

The point-slope form of an equation of a line:

$y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}$

We have two points (-6, 5) and (8, 14).

Substitute:

$m=\dfrac{14-5}{8-(-6)}=\dfrac{9}{14}\\\\y-5=\dfrac{9}{14}(x-(-6))\\\\y-5=\dfrac{9}{14}(x+6)$

Thew standard form of an equation of a line:

$Ax+By=C$

transform:

$y-5=\dfrac{9}{14}(x+6)\qquad|\text{multiply both sides by 14}\\\\14y-14\cdot5=14\!\!\!\!\!\diagup^1\cdot\dfrac{9}{14\!\!\!\!\!\diagup_1}(x+6)\\\\14y-70=9(x+6)\\\\14y-70=9x+54\qquad|\text{subtract}\ 9x\ \text{from both sides}\\\\-9x+14y-70=54\qquad|\text{add 70 to both sides}\\\\-9x+14y=70\qquad|\text{change the signs}\\\\9x-14y=-70$