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3 years ago

(4x2-25)/(2x2+3x-20) Simplify the expression

Mathematics

1 answer:

mr Goodwill [35]3 years ago

3 0

Answer:

$\frac{-17}{16+3x}$

Step-by-step explanation:

8-25

4+3x-20

-17

16+3x

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Given the two Fibonacci numbers below, which number would follow? F(14) = 377 and F(15) = 610

beks73 [17]

Answer:

987.

Step-by-step explanation:

The terms in a Fibonacci series are obtained form the sum of the previous 2 terms. So the next number F(16) = 377 + 610 = 987.

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4 years ago

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Joe told Mickey he got an hourly raise at work and his new rate will be $10.25 per hour. Mickey wants to know what Joe’s hourly

Mamont248 [21]

10.25-r is your answer.

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3 years ago

Which is the equation for the nth term of the geometric sequence: -4,8,-16...?

kobusy [5.1K]

Answer:

aₙ=(-2)ⁿ*2.

Step-by-step explanation:

1) -4*(-2)=8; 8*(-2)=-16; -16*(-2)=32, ...

2) the required equation is:

aₙ=(-1)ⁿ*2ⁿ*2; ⇒ aₙ=(-2)ⁿ*2 or aₙ=(-1)ⁿ*2ⁿ⁺¹.

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2 years ago

A vertical cylinder is leaking water at a rate of 4m3/sec. If the cylinder has a height of 10m and a radius of 2m, at what rate

Katyanochek1 [597]

Answer:

Therefore the rate change of height is $\frac{1}{\pi}$ m/s.

Step-by-step explanation:

Given that a vertical cylinder is leaking water at rate of 4 m³/s.

It means the rate change of volume is 4 m³/s.

$\frac{dV}{dt}=4 \ m^3/s$

The radius of the cylinder remains constant with respect to time, but the height of the water label changes with respect to time.

The height of the cylinder be h(say).

The volume of a cylinder is $V=\pi r^2 h$

$=( \pi \times 2^2\times h)\ m^3$

$\therefore V= 4\pi h$

Differentiating with respect to t.

$\frac{dV}{dt}=4\pi \frac{dh}{dt}$

Putting the value $\frac{dV}{dt}$

$\Rightarrow 4\pi \frac{dh}{dt}=4$

$\Rightarrow \frac{dh}{dt}=\frac{4}{4\pi}$

$\Rightarrow \frac{dh}{dt}=\frac{1}{\pi}$

The rate change of height does not depend on the height.

Therefore the rate change of height is $\frac{1}{\pi}$ m/s.

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3 years ago

Find the exact solution of the equation. 7^x=8

evablogger [386]

Answer:

$log_{7}(8)$

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3 years ago